All categories

2 years ago

How do I find measure of center on a right skewed distribution?

Mathematics

1 answer:

andrew11 [14]2 years ago

8 0

You should try find the median

You might be interested in

Evaluate x4 + 4x3 - 2x2 + 11x - 6 for x = 3

erica [24]

Step-by-step explanation:

$f(x) = {x}^{4} + 4 {x}^{3} - 2 {x}^{2} + 11x - 6$

$f(3) = {3}^{4} + 4. {3}^{3} - 2. {3}^{2} + 11.3 - 6$

$f(3) = 81 + 4.27 - 2.9 + 33 - 6$

$f(3) = 81 + 108 - 18 + 33 - 6$

$f(3) = 198$

8 0

2 years ago

Read 2 more answers

Danny bought 5 Pes to $0.30 each six pencils at $0.25 since in The Notebook for $3 and the tax is $8 how much did he pay will ma

Paha777 [63]

The answer is 14. This is because 0.30 multiplied by 5 is 1.5. Then 6 multiplied by 0.25 is 1.5 as well. Adding these two together is 3. 3 plus 3 for the notebook is 6. Than 6 plus 8 dollar tax is 14 dollars.

6 0

2 years ago

'find the equation of the line shown':

insens350 [35]

Answer:

y = x + 6

Step-by-step explanation:

The y-intercept is (0, 6). This is where the line crosses the y-axis.

The slope is 4/4, or 1: m = 1

The equation of the line is therefore y = x + 6

4 0

3 years ago

James divided 144 ounces of water evenly among 4 containers. One of the containers leaked 8 ounces.

Verdich [7]

Answer:

I dont understand your question rither

Step-by-step explanation:

sorry I would help is I neew

3 0

2 years ago

A 2.2 kg ball strikes a wall with a velocity of 7.4 m/s to the left. The ball bounces off with a velocity of 6.2 m/s to the righ

Naya [18.7K]

Answer:

The constant force exerted on the ball by the wall is 119.68 N.

Step-by-step explanation:

Consider the provided information.

It is given that the mass of the ball is m = 2.2 kg

The initial velocity of the ball towards left is 7.4 m/s

So the momentum of the ball when it strikes is = $2.2\times 7.4=16.28$

The final velocity of the ball is -6.2 m/s

So the momentum of the ball when it strikes back is = $2.2\times -6.2=-13.64$

Thus change in moment is: $16.28-(-13.64)=29.92$

The duration of force exerted on the ball t = 0.25 s

Therefore, the constant force exerted on the ball by the wall is:

$\frac{29.92}{0.25}=119.68$

Hence, the constant force exerted on the ball by the wall is 119.68 N.

6 0

3 years ago

How do I find measure of center on a right skewed distribution?​

How do I find measure of center on a right skewed distribution?