Question

NASA launches a rocket at t = 0 seconds. Its height, in meters above sea-level, as a function of time is given by h ( t ) = − 4.9 t 2 + 178 t + 325 . Assuming that the rocket will splash down into the ocean, at what time does splashdown occur? The rocket splashes down after how many seconds

Answer 1

Answer:

The rock splashes down when h(t) = 0. Set h(t) = 0 and solve for t using quadratic formula.

0 = − 4.9t^2 + 178t + 325

t = 38.07, -1.74

(Throw away the negative answer, since time can't be negative.)

t = 38.07 sec

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