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REY [17]
3 years ago
7

Suppose that you want to mix two coffees in order to obtain 100 pounds of a blend. If x represents the number of pounds of coffe

e​ A, write an algebraic expression that represents the number of pounds of coffee B.
An algebraic expression that represents the number of pounds of coffee B is
nothing.​(Type an expression using x as the​ variable.)
Mathematics
1 answer:
Fantom [35]3 years ago
8 0

Answer:

The required expression that represents the number of pound of coffees B is 100-x

Step-by-step explanation:

Consider the provided information.

You want to mix two coffees in order to obtain 100 pounds of a blend.

Let x represents the number of pounds of coffee​ A and y represents the number of pounds of coffee​ B.

The obtained weight is 100 pounds.

x+y=100

y=100-x

Hence, the required expression that represents the number of pound of coffees B is 100-x

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

The difference is 75% of 12 oz, so is ...

  0.75 · 12 oz = 9 oz

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6 0
3 years ago
In recent commercials Toyota claimed that 80% of its vehicles sold in the past 20 years are still on the road. You work for an a
Anvisha [2.4K]

Answer:

Step-by-step explanation:

We have to perform one sample proportion test. To do so we have to proceed through following steps.

(1) We have to collect data about vehicle sales in last 20 years.

(2) Using random number table or random number generator or otherwise we have to select sample of vehicles from the list of sale. In this step, we have to keep an eye on the fact that sample is to be selected from all years (all of 20). Using stratified random sampling by dividing vehicles sold over different years is an effective way to do so. That means, we may divide vehicles sold into 20 homogeneous strata over 20 years and select sample from each strata.

(3) After selecting sample of vehicles we have to communicate to corresponding vehicle owners to gather information about that particular vehicle.

(4) We have to note number of vehicles which are still on the road.

Suppose, we have selected  n vehicles as sample and after communicating we found that \tiny r of those are still on the road.

We have to test for null hypothesis H_0:p=0.80

against the alternative hypothesis H_1 \neq 0.80

Our test statistic is given

z=\frac{\hat p - p_0}{\sqrt{p_0(1-p_0)/n} }

here,

\hat p =\frac{r}{n}

p_0 =0.80

z=\frac{r/n-0.80\sqrt{n} }{0.40} \\\\=2.5(\frac{r}{n} -0.8)\sqrt{n}

We then calculate corresponding p-value.

We reject our null hypothesis if \text{p-value} , level of significance.

According to our obtained p-value and level of significance we proceed to certain conclusion.

8 0
3 years ago
You are planning on retiling your bathroom floor and buy 96 square feet of tile. If the length of the bathroom is
Rudik [331]

Answer:

8 feet

Step-by-step explanation:

Given that 96 sq. feet of tile is bought to retile the bathroom.

It means area of bathroom is 93/2 x^2 = 96\\=> 3 x^2 = 96*2=192\\=>  x^2 = 192/3 = 64\\=>\sqrt{x^2}  = \sqrt{64} \\=> x = 86 sq. feet

Width of bathroom be x

Given that the length of the bathroom is  one and a half times the width

Length of bathroom in term sod width = 1 1/2* x = 3/2 x

we know area of rectangle is given by length * width

therefore area of bathroom =( x* 3/2 x) = 3/2 x^2

Also area of  bathroom is 86 sq. feet, therefore

3/2 x^2 = 96\\=> 3 x^2 = 96*2=192\\=>  x^2 = 192/3 = 64\\=>\sqrt{x^2}  = \sqrt{64} \\=> x = 8

Thus, width of bathroom is 8 feet.

4 0
3 years ago
f the price charged for a candy bar is​ p(x) cents, where p (x )equals 162 minus StartFraction x Over 10 EndFraction ​, then x t
andreev551 [17]

Answer:

a. 1620-x^2

b. x=810

c. Maximum value revenue=$656,100

Step-by-step explanation:

(a) Total revenue from sale of x thousand candy bars

P(x)=162 - x/10

Price of a candy bar=p(x)/100 in dollars

1000 candy bars will be sold for

=1000×p(x)/100

=10*p(x)

x thousand candy bars will be

Revenue=price × quantity

=10p(x)*x

=10(162-x/10) * x

=10( 1620-x/10) * x

=1620-x * x

=1620x-x^2

R(x)=1620x-x^2

(b) Value of x that leads to maximum revenue

R(x)=1620x-x^2

R'(x)=1620-2x

If R'(x)=0

Then,

1620-2x=0

1620=2x

Divide both sides by 2

810=x

x=810

(C) find the maximum revenue

R(x)=1620x-x^2

R(810)=1620x-x^2

=1620(810)-810^2

=1,312,200-656,100

=$656,100

7 0
4 years ago
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