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REY [17]
3 years ago
7

Suppose that you want to mix two coffees in order to obtain 100 pounds of a blend. If x represents the number of pounds of coffe

e​ A, write an algebraic expression that represents the number of pounds of coffee B.
An algebraic expression that represents the number of pounds of coffee B is
nothing.​(Type an expression using x as the​ variable.)
Mathematics
1 answer:
Fantom [35]3 years ago
8 0

Answer:

The required expression that represents the number of pound of coffees B is 100-x

Step-by-step explanation:

Consider the provided information.

You want to mix two coffees in order to obtain 100 pounds of a blend.

Let x represents the number of pounds of coffee​ A and y represents the number of pounds of coffee​ B.

The obtained weight is 100 pounds.

x+y=100

y=100-x

Hence, the required expression that represents the number of pound of coffees B is 100-x

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Can someone please find the value of X for these two questions?
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Giselle spent 7/10 of her money on a book and 10/100 of her money on food. What fraction of her money did she spend altogether?
aleksklad [387]

Answer:

80/100 or 80%

Step-by-step explanation:

7/10 = 70/100

70/100 + 10/100 = 80/100

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3 years ago
Read 2 more answers
#1 Find the slope given the points (3,-20) and (5,8) *
Artyom0805 [142]

Hey there :)

To find the slope with <em>two points</em> we will need to use the equation  \frac{y^2-y^1}{x^2-x^1}

x^1    x^2       y^1  y^2

( 3 , -20 )  ( 5 , 8 )

Here is what the equation should look like when replaced with the numbers (<em>it will be a fraction</em>) :

                                     \frac{8 - (-20)}{5 - 3}

We know that <em>two negatives</em> cancel out and make a positive, so the numerator would actually be 8 + 20.

Solve the fraction and we get   \frac{28}{2}

28 <em>divided</em> by 2 is 14. The slope is 14.

6 0
3 years ago
What is the answer and how do you solve <br><br><br> 21x^3/3x^−1
Sunny_sXe [5.5K]

Answer:

  as written: 7x^2

  perhaps intended: 7x^4

Step-by-step explanation:

As written, the Order of Operations specifies that the only denominator factor is 3, so the expression is interpreted as ...

  \dfrac{21x^3}{3}x^{-1}=\dfrac{21}{3}x^{3-1}=7x^2

___

Sometimes grouping of denominator factors is intended, but parentheses are not written as they should be. If the intention is ...

  21x^3/(3x^-1)

then the simplification is ...

  \dfrac{21x^3}{3x^{-1}}=\dfrac{21}{3}x^{3-(-1)}=7x^4

_____

The applicable rules of exponents are ...

  (a^b)(a^c) = a^(b+c)

  a^b/a^c = a^(b-c)

6 0
3 years ago
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