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2 years ago

Help please ! it’s one of the multiple choices

Mathematics

1 answer:

sammy [17]2 years ago

3 0

Answer:

Option C

Step-by-step explanation:

$\boxed{Log \ \dfrac{a}{b}=log \ a - log \ b}\\\\\boxed{(log \ a)^b=b*log \ a}$

$\sf log_w \ \dfrac{(x^{2}-6)^4}{\sqrt[3]{x^2+8} }=log_w \ (x^2-6)^4 - log_w(x^2+8)^{\frac{1}{3}}$

$\sf = 4*log_w \ (x^2 -6) - \dfrac{1}{3}log_w \ (x^2 + 8)$

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(PLS help I’ll give brainliest to whoever can answer right nobody has been able to. )

natali 33 [55]

Volume of a cone = 3.14 x 0.75^2 x 2/3
= 3.14 x 0.5625 x 2/3
= 1.76625 x 2/3
= 1.1775 = 1.18 feet^3

3 0

2 years ago

Helpp me pleasee.....

meriva

300; Since EF is the only segment not included in FHE, just subtract the 60 degrees there from 360 to get the sum of the rest of the circle

360-60 = 300

Hopefully this is right, i'm a little rusty on geometry

4 0

3 years ago

Hi i need help below thank you 32 POINTS

lara [203]

A = (pi) * r*2
(pi) = 3.14
r = d/2.....r = 17/2 or 8.5

A = 3.14 * 8.5^2
A = 3.14 * 72.25
A = 226.86 rounds to 226.9 m^2 <==

6 0

3 years ago

Suppose that two openings on an appellate court bench are to be filled from current municipal court judges. The municipal court

Ksju [112]

Answer:

$(a)\dfrac{92}{117}$

$(b)\dfrac{8}{39}$

$(c)\dfrac{25}{117}$

Step-by-step explanation:

Number of Men, n(M)=24

Number of Women, n(W)=3

Total Sample, n(S)=24+3=27

Since you cannot appoint the same person twice, the probabilities are <u>without replacement.</u>

(a)Probability that both appointees are men.

$P(MM)=\dfrac{24}{27}X \dfrac{23}{26}=\dfrac{552}{702}\\=\dfrac{92}{117}$

(b)Probability that one man and one woman are appointed.

To find the probability that one man and one woman are appointed, this could happen in two ways.

A man is appointed first and a woman is appointed next.
A woman is appointed first and a man is appointed next.

P(One man and one woman are appointed) $=P(MW)+P(WM)$

$=(\dfrac{24}{27}X \dfrac{3}{26})+(\dfrac{3}{27}X \dfrac{24}{26})\\=\dfrac{72}{702}+\dfrac{72}{702}\\=\dfrac{144}{702}\\=\dfrac{8}{39}$

(c)Probability that at least one woman is appointed.

The probability that at least one woman is appointed can occur in three ways.

A man is appointed first and a woman is appointed next.
A woman is appointed first and a man is appointed next.
Two women are appointed

P(at least one woman is appointed) $=P(MW)+P(WM)+P(WW)$

$P(WW)=\dfrac{3}{27}X \dfrac{2}{26}=\dfrac{6}{702}$

In Part B, $P(MW)+P(WM)=\frac{8}{39}$

Therefore:

$P(MW)+P(WM)+P(WW)=\dfrac{8}{39}+\dfrac{6}{702}\\$P(at least one woman is appointed)=\dfrac{25}{117}$

5 0

3 years ago

Please help me out :)

arlik [135]

Answer:

$\frac{\sqrt{17} }{7}$

Step-by-step explanation:

Using the Pythagorean identity

sin²x + cos²x = 1, then

sinx = $\sqrt{1-cos^2x}$

Note that ( $\frac{4\sqrt{2} }{7}$ )² = $\frac{32}{49}$

sinΘ = $\sqrt{1-(32/49)}$

= $\sqrt{\frac{17}{49} }$ = $\frac{\sqrt{17} }{7}$

5 0

3 years ago