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2 years ago

Help please ! it’s one of the multiple choices

Mathematics

1 answer:

sammy [17]2 years ago

3 0

Answer:

Option C

Step-by-step explanation:

$\boxed{Log \ \dfrac{a}{b}=log \ a - log \ b}\\\\\boxed{(log \ a)^b=b*log \ a}$

$\sf log_w \ \dfrac{(x^{2}-6)^4}{\sqrt[3]{x^2+8} }=log_w \ (x^2-6)^4 - log_w(x^2+8)^{\frac{1}{3}}$

$\sf = 4*log_w \ (x^2 -6) - \dfrac{1}{3}log_w \ (x^2 + 8)$

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URGENT HELP ME PLEASE

Trava [24]

Answer:

(a) $\log_3(\dfrac{81}{3})=3$

(b) $\log_5(\dfrac{625}{25})=2$

(d) $\log_4(\dfrac{64}{16})=1$

(e) $\log_6(36^4)=8$

(f) $\log(100^3)=6$

Step-by-step explanation:

Let as consider the given equations are $\log_3(\dfrac{81}{3})=?,\log_5(\dfrac{625}{25})=?,\log_2(\dfrac{64}{8})=?,\log_4(\dfrac{64}{16})=?,\log_6(36^4)=?,\log(100^3)=?$ .

(a)

$\log_3(\dfrac{81}{3})=\log_3(27)$

$\log_3(\dfrac{81}{3})=\log_3(3^3)$

$\log_3(\dfrac{81}{3})=3$ $[\because \log_aa^x=x]$

(b)

$\log_5(\dfrac{625}{25})=\log_5(25)$

$\log_5(\dfrac{625}{25})=\log_5(5^2)$

$\log_5(\dfrac{625}{25})=2$ $[\because \log_aa^x=x]$

(c)

$\log_2(\dfrac{64}{8})=\log_2(8)$

$\log_2(\dfrac{64}{8})=\log_2(2^3)$

$\log_2(\dfrac{64}{8})=3$ $[\because \log_aa^x=x]$

(d)

$\log_4(\dfrac{64}{16})=\log_4(4)$

$\log_4(\dfrac{64}{16})=1$ $[\because \log_aa^x=x]$

(e)

$\log_6(36^4)=\log_6((6^2)^4)$

$\log_6(36^4)=\log_6(6^8)$

$\log_6(36^4)=8$ $[\because \log_aa^x=x]$

(f)

$\log(100^3)=\log((10^2)^3)$

$\log(100^3)=\log(10^6)$

$\log(100^3)=6$ $[\because \log10^x=x]$

5 0

3 years ago

What’s the property of 45 times 6

lidiya [134]

Answer:

270

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

How can you represent all of the solutions to systems of inequalities?

Dimas [21]

Answer:A closed, or shaded, circle is used to represent the inequalities greater than or equal to (≥) or less than or equal to (≤) . The point is part of the solution. An open circle is used for greater than (>) or less than (<). The point is not part of the solution. Solving" systems of linear inequalities means "graphing each individual inequality, and then finding the overlaps of the various solutions". So I graph each inequality, and then find the overlapping portions of the solution regions.Step 1: Line up the equations so that the variables are lined up vertically. Step 2: Choose the easiest variable to eliminate and multiply both equations by different numbers so that the coefficients of that variable are the same. Step 3: Subtract the two equations. Step 4: Solve the one variable system.

Step-by-step explanation:

hope this helps have a great night ❤️❤️❤️

6 0

3 years ago

What is the solution to –2(8x – 4) < 2x + 5?

Contact [7]

The solution to –2(8x – 4) < 2x + 5 is x > 1/6

<h3>How to solve the inequality?</h3>

The expression is given as:

–2(8x – 4) < 2x + 5

Expand

-16x + 8 < 2x + 5

Evaluate the like terms

-18x < -3

Divide both sides by -18

x > 1/6

Hence, the solution to –2(8x – 4) < 2x + 5 is x > 1/6