Answer:
The signal would have experienced aliasing.
Step-by-step explanation:
Given that:
the bandwidth of the signal
= 36MHz
= 36 × 10⁶ Hz
The sampling frequency
= 36 × 10⁶ Hz
Suppose the sampling frequency is equivalent to the bandwidth of the signal, then aliasing will occur.
Therefore, according to the Nyquist criteria;
Nyquist criteria posit that if the sampling frequency is more above twice the maximum frequency to be sampled, a repeating waveform can be accurately reconstructed.
∴
By Nyquist criteria, for perfect reconstruction of an original signal, i.e. the received signal without aliasing effect;
Then,

∴
The signal would have experienced aliasing.
69.24 because you round the three up
Answer:
12times10+5 -3+5-7times305
162=470m+b and 183=540m+b.
183-162=(540-470)m, 21=70m so m=0.30.
162=470×0.30+b=141+b, b=162-141=21
Therefore y=0.30m+21.
Your answer would be 12 because the green is half of the red in which it is now 2, 5, and 1.5 we multiply these numbers together and get the volume in which the answer is 12 (: hope I could help, if you could make me brainalist that would amazing!