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Murljashka [212]
2 years ago
9

Lol

Mathematics
1 answer:
zavuch27 [327]2 years ago
5 0

The centers and radius for the equations are:

  • 1) (1, 6) and radius 3
  • 2) (2, -3) and radius 6
  • 3) (-4, 5) and radius 5

And the circles are in the graph below.

<h3>How to identify the center and radius of a circle?</h3>

A general circle equation centered at the point (a, b), with a radius of R, is written as:

(x - a)^2 + (y - b)^2 = R^2

Then for the given equations we have:

1) (y-6)^2 + (x - 1)^2 = 9

So the center is at (1, 6) and the radius is 3.

2)  (x-2)^2 + (y + 3)^2 = 36 = 6^2

So the center is at (2, -3) and the radius is 6.

3) (x + 4)^2 +(y-5)^2 = 25 = 5^2

So the center is at (-4, 5) and the radius is 5.

The graphs of the 3 circles can be seen below. Green is the first circle, blue is the second circle, and red is the last circle.

If you want to learn more about circles, you can read:

brainly.com/question/1559324

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You roll a standard number cube. Find p(number greater than 2)
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A number cube contains the numbers 1-6. Without counting the numbers that are less than two, you will get 3, 4, 5, and 6.
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4 years ago
5.Solve the quadratic equation.
Dafna1 [17]

Answer:

x=5 twice

Step-by-step explanation:

x^2-10x+25=0

multiply the coefficient of x^2 and the last term

1X25=25

find two numbers you can multiply to get 25 and add to get -10

-5 + (-5)=-10 the middle term

replace -10x with -5x -5x and solve the equation

x^2-5x-5x+25=0

factorise by grouping

x(x-5)-5(x-5)=0

(x-5)(x-5)=0

Either x-5=0,x=5 or x-5=0,x=5

Therefore x=5 twice.

5 0
4 years ago
How does the position of the decimal point in a quotient as you divide by increasing powers of 10
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4 0
4 years ago
WRITE THE expression in complete factored form 2y^2(p-4)-7(p-4)
Aleonysh [2.5K]
P - 4 is common to  the 2 parts so we have

(2y^2 - 7)(p - 4)  Answer
5 0
4 years ago
Read 2 more answers
The combined math and verbal scores for students taking a national standardized examination for college admission, is normally d
kipiarov [429]

Answer:

The minimum score that such a student can obtain and still qualify for admission at the college = 660.1

Step-by-step explanation:

This is a normal distribution problem, for the combined math and verbal scores for students taking a national standardized examination for college admission, the

Mean = μ = 560

Standard deviation = σ = 260

A college requires a student to be in the top 35 % of students taking this test, what is the minimum score that such a student can obtain and still qualify for admission at the college?

Let the minimum score that such a student can obtain and still qualify for admission at the college be x' and its z-score be z'.

P(x > x') = P(z > z') = 35% = 0.35

P(z > z') = 1 - P(z ≤ z') = 0.35

P(z ≤ z') = 1 - 0.35 = 0.65

Using the normal distribution table,

z' = 0.385

we then convert this z-score back to a combined math and verbal scores.

The z-score for any value is the value minus the mean then divided by the standard deviation.

z' = (x' - μ)/σ

0.385 = (x' - 560)/260

x' = (0.385×260) + 560 = 660.1

Hope this Helps!!!

8 0
4 years ago
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