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tresset_1 [31]
3 years ago
5

1,320 tickets were sold for a total amount of $7,815.00. If each student ticket costs $3.00, and each adult ticket costs $6.00.

Write the systems of equation that allows you to calculate how many student tickets were purchased.
Mathematics
1 answer:
cestrela7 [59]3 years ago
3 0

Answer: oh my

Step-by-step explanation:

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What is 23-5 <br><img src="https://tex.z-dn.net/?f=18" id="TexFormula1" title="18" alt="18" align="absmiddle" class="latex-formu
zheka24 [161]
23 minus 5 equals 18
5 0
4 years ago
Read 2 more answers
Two dice are rolled. Determine the probability of the following: rolling a 6 or doubles
gtnhenbr [62]

Answer as an exact fraction = 5/18

Answer as an approximate decimal = 0.2778

Answer as an approximate percentage = 27.78%

============================================================

Explanation:

x = result of the first die

y = result of the second die

(x,y) paired together shows the results of both dice at the same time.

Something like (x,y) = (4,2) means we got 4 on the first die and 2 on the second die.

--------

Let's list the ways of rolling a 6

  • (1,5)
  • (2,4)
  • (3,3)
  • (4,2)
  • (5,1)

There are 5 ways to roll a 6. Each pair listed has the property x+y = 6.

--------

List all the ways of getting doubles

  • (1,1)
  • (2,2)
  • (3,3)
  • (4,4)
  • (5,5)
  • (6,6)

There are 6 ways to roll doubles. Each pair mentioned has x = y.

--------

We have 5+6 = 11 items listed above. However, there are only 10 unique pairs though because (3,3) was listed twice. So we could say 5+6-1 = 11-1 = 10.

This is out of 6*6 = 36 different ways to roll the two dice. The probability is therefore 10/36 = 5/18.

Using a calculator, 5/18 = 0.2778 = 27.78%

7 0
4 years ago
Help me plz!!!!!!!!!!!!!!!!
mixer [17]

Answer:

Graph A

Step-by-step explanation:

-y=-2-3x

y=3x+2

Slope:3

y-intercept:2

5 0
3 years ago
Suppose each of 12 players rolls a pair of dice 3 times. Find the probability that at least 4 of the players will roll doubles a
polet [3.4K]

Answer:

Our answer is 0.8172

Step-by-step explanation:

P(doubles on a single roll of pair of dice) =(6/36) =1/6

therefore P(in 3 rolls of pair of dice at least one doubles)=1-P(none of roll shows a double)

=1-(1-1/6)3 =91/216

for 12 players this follows binomial distribution with parameter n=12 and p=91/216

probability that at least 4 of the players will get “doubles” at least once =P(X>=4)

=1-(P(X<=3)

=1-((₁₂ C0)×(91/216)⁰(125/216)¹²+(₁₂ C1)×(91/216)¹(125/216)¹¹+(₁₂ C2)×(91/216)²(125/216)¹⁰+(₁₂ C3)×(91/216)³(125/216)⁹)

=1-0.1828

=0.8172

7 0
4 years ago
Please help and explain would I still set this up with law of sine or use cosine
Svetach [21]

You would use the tangent first, because the opposite of 40 would be x and the adjacent would be 30ft

4 0
3 years ago
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