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2 years ago

14

Can someone help me with this? I need it before Monday. I will give brainlist!! If the picture is too blurry here is the problem

:
Michelle makes jewelry boxes containing drawers of equal size. The numbers of drawers in three ditterent ewelry boxes and the corresponding total volumes of the drawers are shown in the table below. JEWELRY BOXES Number of Drawers Total Volume (cubic inches) 2 5 3 7.5 4 +6 10 Write an equation for the relationship between the number of drawers in the jewelry box, d, and the total volume of the drawers in the jewelry box, V. Use your equation to determine the number of drawers in a jewelry box with a total volume of 17.5 cubic inches Show your work.

1 answer:

tigry1 [53]2 years ago

6 0

Answer:

1. total volume of box=2.5(V)D

2. 7 Drawers

Step-by-step explanation:

2.5 = V

so 1 draw = 2.5 cubic inches of volume

so V(2.5) × D(number of drawers) = total volume of drawers in the box

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Please guys help me with this. I will give you brainliest. please ❤❤

yawa3891 [41]

Answer:

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Step-by-step explanation:

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4 0

3 years ago

Read 2 more answers

What is 9x + 18 = 6y - 3x for y

Nana76 [90]

Answer: 2x+3

Step-by-step explanation:

9x+18=6y-3x Our goal is to isolate y.

Let's add 3x to both sides of the equation to cancel out that -3x on the right side.

12x+18=6y Because all of these integers are divisible by the gcf of 6, we can divide both sides of the equation by 6.

2x+3=y

4 0

3 years ago

Please Help me! Algebra 1

dem82 [27]

Option a: The number of bacteria at time x is 0.

Option b: An exponential function that represents the population is $y=200(1.5)^x$

Option c: The population after 10 minutes is 11534(app)

Explanation:

It is given that the coordinates of the graph are (0,200), (1,300) and (2, 450)

Option a: To determine the number of bacteria x when y = 200

From the graph, we can see that the line meets y = 200 when x = 0

Thus, the coordinates are (0,200)

Hence, the number of bacteria at time x is 0 when y = 200.

Option b: Now, we shall determine the exponential function of the population.

The general formula for exponential function is $y=a \cdot b^{x}$

Where a is the starting point and $a=200$

b is the common difference.

To determine the common difference, let us divide,

$\frac{300}{200} =1.5$

Also, $\frac{450}{300} =1.5$

Hence, the common difference is $b=1.5$

Thus, substituting the values $a=200$ and $b=1.5$ in the formula $y=a \cdot b^{x}$ ,

we have, $y=200(1.5)^x$

Hence, An exponential function that represents the population is $y=200(1.5)^x$

Option c: To determine the population after 10 minutes, let us substitute $x=10$ in $y=200(1.5)^x$ , since the x represents the population of the bacteria in minutes.

Thus, we have,

$\begin{aligned}y &=200(1.5)^{x} \\&=200(1.5)^{10} \\&=200(57.67) \\&=11534\end{aligned}$

Hence, the population after 10 minutes is 11534(app)

7 0

3 years ago

During 4 days, the price of the stock of PEV Corporation went up 1/4 of a point, down 1/3 of a point, down 3/4 of a point, and u

HACTEHA [7]

The price of the stock of PEV Corporation varies as shown. we have to determine the net charge. Net change is just how much it changed overall, so we will look for all the ups minus all the downs.

Here, "went up" goes with a + sign, and "went down" goes with a - sign.

So, Net charge = $\frac{1}{4} - \frac{1}{3}-\frac{3}{4} + \frac{7}{10}$

= $\frac{1}{4}-\frac{3}{4}- \frac{1}{3} + \frac{7}{10}$

= $-\frac{2}{4}- \frac{1}{3} + \frac{7}{10}$

= $-\frac{1}{2}- \frac{1}{3} + \frac{7}{10}$

LCM of 2,3 and 10 is 30

= $\frac{-15-10+21}{30}$

= $\frac{-4}{30}$

= $\frac{-2}{15}$

So, the net charge is $\frac{-2}{15}$

8 0

2 years ago

Using a linear approximation, estimate f(2.1), given that f(2) = 5 and f'(x) = √3x-1.

algol [13]

Answer:

$f\left( {2.1} \right) \approx 5.22360$ .

Step-by-step explanation:

The linear approximation is given by the equation

${f\left( x \right) \approx L\left( x \right) }={ f\left( a \right) + f^\prime\left( a \right)\left( {x - a} \right).}$

Linear approximation is a good way to approximate values of $f(x)$ as long as you stay close to the point $x= a$ , but the farther you get from $x=a$ , the worse your approximation.

We know that,

$a=2\\f(2) = 5\\f'(x) = \sqrt{3x-1}$

Next, we need to plug in the known values and calculate the value of $f(2.1)$ :

${L\left( x \right) = f\left( 2 \right) + f^\prime\left( 2 \right)\left( {x - 2} \right) }=5+\sqrt{3(2)-1}(x-2) =5+\sqrt{5}(x-2)$

Then

$f\left( {2.1} \right) \approx 5+\sqrt{5}(2.1-2)\approx5.22360$ .

6 0

3 years ago