All categories

2 years ago

Tamara attends a cycling class that starts at 6:00. The class lasts 45 minutes. What time does class end?

Mathematics

1 answer:

KonstantinChe [14]2 years ago

3 0

Answer: C. 45 minutes before 7:00

Hope this helps! :)

Brainliest please.

You might be interested in

Heeeeeeeeeellllllllllp!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Leto [7]

Question number one is B. Multiplication Property of Equality

6 0

3 years ago

Read 2 more answers

£980 is divided between Caroline, Sarah & Gavyn so that Caroline gets twice as much as Sarah, and Sarah gets three times as

Nitella [24]

Sarah has received £ 294

Solution:

Given that £980 is divided between Caroline, Sarah & Gavyn

Let "c" be the amount received by caroline

Let "s" be the amount received by sarah

Let "g" be the amount received by gavyn

Caroline gets twice as much as Sarah

amount received by caroline = twice as much as Sarah

amount received by caroline = 2(amount received by sarah)

c = 2s ---- eqn 1

Sarah gets three times as much as Gavyn

amount received by sarah = three times as much as Gavyn

amount received by sarah = 3(amount received by gavyn)

s = 3g ------- eqn 2

Given that total amount is 980

c + s + g = 980 --- eqn 3

Let us solve eqn 1, 2, 3 to get values of "c" "s" "g"

From eqn 2,

$g = \frac{s}{3}$ --- eqn 4

Substitute eqn 1 and eqn 4 in eqn 3

$2s + s + \frac{s}{3} = 980\\\\\frac{6s + 3s + s}{3} = 980\\\\6s + 3s + s = 980 \times 3\\\\10s = 2940\\\\s = 294$

Thus sarah has received £ 294

7 0

3 years ago

The length of the segment between the points $(2a, a-4)$ and $(4, -1)$ is $2\sqrt{10}$ units. What is the product of all possibl

True [87]

Answer:

-3

Step-by-step explanation:

The length of a segment is

sqrt( ( y2-y1)^2 + (x2-x1) ^2) = 2 sqrt(10)

sqrt( ( a-4 - -1)^2 + (2a -4) ^2) = 2 sqrt(10)

sqrt( ( a-4 +1)^2 + (2a -4) ^2) = 2 sqrt(10)

Combine like terms

sqrt( ( a-3)^2 + (2a -4) ^2) = 2 sqrt(10)

Square each side

( a-3)^2 + (2a -4) ^2) = 4 *(10)

FOIL the left side

a^2 -6a +9 + 4a^2 -16a +16 = 40

Combine like terms

5a^2 -22a +25 = 40

Subtract 40 from each side

5a^2 -22a -15 =0

Factor

(a - 5) (5 a + 3) = 0

Using the zero product property

a-5 =0 5a +3 = 0

a = 5 5a = -3

a=5 a = -3/5

The product of the terms is

5 * -3/5 = -3

5 0

3 years ago

The school's production of Romeo and Juliet began at 7:30 P.M. The first act lasted 1 hour and 45 minutes. The act was followed

kkurt [141]

The second act began at 9:35.

3 0

3 years ago

Read 2 more answers

HELP!!! ASAP!!! You expand a rectangular garden so the perimeter is now twice the perimeter of the old garden. The expression 12

Soloha48 [4]

Answer:

a) Perimeter of old garden=6w+8

b) A = 2W^2+4W

Step-by-step explanation:

old Area = length * width

= L * W

the old perimeter = half of the new one, so it is 6w+8

the old perimeter has to equal 2L + 2W

2L+2W=6W+8

2L=4W+8

L=2W+4

Area=L*W

A=(2W+4)(W)

=2W^2+4W

5 0

3 years ago