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IRINA_888 [86]
3 years ago
5

8m-6(-8m+4)= ??????????????????

Mathematics
1 answer:
dangina [55]3 years ago
5 0
The answer is 8m im serious
You might be interested in
Help me please please
Marrrta [24]

Answer:

a.11

b.20

c.44

d.5

e.60

f.12

g.4

h.40

i.900

j.6

Step-by-step explanation:

hope this helps

8 0
2 years ago
Round 915 to the nearest ten
solong [7]
920 because 15 is closer to 20 than to 10
6 0
3 years ago
Does anyone know this?
Bumek [7]

Answer:

B

Step-by-step explanation:

Initial mean = 156, Changed mean = 163.92

So, mean increases. Only condition that satisfies this is B.

7 0
3 years ago
Here are some prices customers paid for different items at a farmer’s market. Find the cost for 1 pound of each item.
posledela

Answer:

  • 1 pounds of apples = \1·25
  • 1 pounds of cheese = \7
  • 1 pounds of coffee beans = \5·5
  • 1 pounds of fudge = \9
  • 1 pounds of pumpkin = \0·88

Step-by-step explanation:

Unit Rate is the ratio between two different quantities with different units

The ratio of cost per items is

=  \frac{dollars}{pounds}

4 pounds of apples  = \5

4 pounds = \5

Divided 4 both the side

1 pounds of apples = \1·25

\frac{1}{2} pounds of cheese = \3·50

\frac{1}{2} pounds = \3·50

Divided \frac{1}{2} both the side

1 pounds of cheese = \7

\frac{3}{2} pounds of coffe beans = \8·25

\frac{3}{2} pounds = \8·25

Divided \frac{3}{2} both the side

1 pounds of coffee beans = \5·5

\frac{3}{4} pounds of fudge = \6·75

\frac{3}{4} pounds = \6·75

Divided \frac{3}{4} both the side

1 pounds of fudge = \9

\frac{25}{4} pounds of pumpkin is = \5·50

\frac{25}{4} pounds = \5·50

Divided \frac{25}{4} both the side

1 pounds of pumpkin = \0·88

8 0
3 years ago
Find the sum of and 6/7 and 2/3 express your answer in lowest terms.
tensa zangetsu [6.8K]

Answer:

1 11/21

Step-by-step explanation:

6/7 + 2/3 = 32/21

32/21 simplified is 1 11/21

6 0
3 years ago
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