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lukranit [14]
2 years ago
11

3 (– 8) = 3x – 24 No Solution Infinite Solutions X = -16 D x = 0​

Mathematics
1 answer:
Anettt [7]2 years ago
7 0

Answer:

B Infinite Solutions

Step-by-step explanation:

3 (x - 8) = 3x - 24

3x - 24 = 3x - 24

    + 24        + 24

3x = 3x

x = x

Infinite solutions

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A rectangular prism has a length of 4 cm a width of 6 cm and a height of 3 cm what is it’s volume
liraira [26]

Answer: 72

Step-by-step explanation:

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3 years ago
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Complete the equation of the line through (-6,-5)(−6,−5)(, minus, 6, comma, minus, 5, )and (-4,-4)(−4,−4)(, minus, 4, comma, min
alina1380 [7]

Answer:

y=\frac{1}{2}x-2

Step-by-step explanation:

We have been given two points on a line (-6,-5) and (-4,-4). We are asked to write an equation passing through these points.

We will write our equation in slope-intercept form of equation y=mx+b, where,

m = Slope of line,

b = Initial value or the y-intercept.

Let us find slope of given line using slope formula.

m=\frac{y_2-y_1}{x_2-x_1}

Let point (-6,-5)=(x_1,y_1) and point (-4,-4)=(x_2,y_2).

m=\frac{-4-(-5)}{-4-(-6)}

m=\frac{-4+5}{-4+6}

m=\frac{1}{2}

Now, we will substitute m=\frac{1}{2} and coordinates of point (-6,-5) in slope-intercept form of equation as:

-5=\frac{1}{2}*(-6)+b

-5=-3+b

-5+3=-3+3+b

-2=b

Upon substituting m=\frac{1}{2} and b=-2 in slope-intercept form of equation, we will get our required equation as:

y=\frac{1}{2}x-2

Therefore, our required equation would be y=\frac{1}{2}x-2.

8 0
3 years ago
Find the Value of the letter in the following questions. Give your answers to 3 s.f.
Elis [28]

Answer:

i = 75.7°

h = 48.2°

Step-by-step explanation:

==>To find i, use the sine rule for finding angles: sin(A)/a = sin(B)/b

Where,

a = 7.2cm

sin(A) = i

b = 6.5cm

sin(B) = sin(61) = 0.8746

Thus:

sin(A)/7.2 = 0.8746/6.5

Multiply both sides by 7.2

sin(A) = (0.8746*7.2)/6.5

sin(A) = 0.969 (3 s.f)

A = i° = sin^-1(0.969) = 75.7 (3 s.f)

==>To find h, use the Cosine rule for angles:

Cos(C) = (a²+b²-c²)/2ab

cos(C) = h°, a = 4, b = 4.5, c = 3.5

a² = 16

b² = 20.25

c² = 12.25

cos(C) = (16+20.25-12.25)/(2*4*4.5)

cos(C) = 24/36

cos(C) = 0.667 (3 s.f)

C = h° = cos^-1(0.667) = 48.2° (3 s.f)

4 0
2 years ago
How can you find a ratio in a bar graph​
kap26 [50]

Divine the total number of the entire chart by the number of a single line or bar to give you the ratio in a bar or line chart. For example, if a bar or line represented 5 in a chart with a total of 30, you would divide 30 by 5. This would give you a result of 6. Therefore, the ratio would be 6:1.

6 0
2 years ago
Es 18 de junio de 1815, las tropas napoleónicas se encuentran justo adelante, tu eres el ingeniero en balística y el general Wel
Airida [17]

Answer:

89.1° or -1.4°  

Step-by-step explanation:

1. Location:

You are on the Mont-Saint-Jean escarpment, near the Belgian town of Waterloo.

The French troops are about 50 m below you and 1.2 km distant.

2. Finding the firing angle

Data:

R = 1200 m

u = 600 m/s

h = -50 m (the height of the target)

a = 9.8 m/s²

We have two conditions.

Horizontal distance

(1) 1200 = 600t cosθ

Vertical distance

(2) -50 = 600t sinθ - 4.9t²

Divide each side of (1) by 600cosθ.

(3) \, t =\dfrac{2}{\cos \theta}

Substitute (3) into (2)

-50 = 600t \sin \theta - 4.9t^{2} =  600 \left( \dfrac{2}{\cos \theta} \right ) \sin \theta - 4.9 \left( \dfrac{2}{\cos \theta} \right )^{2}\\\\(4) \, -50 = 1200 \tan \theta - \dfrac{19.6}{\cos^{2} \theta}

Recall that

(5) sec²θ = 1/cos²θ = tan²θ + 1

Substitute (5) into (4)

-50 = 1200 \tan \theta - 19.6 \left(\tan^{2} \theta}+ 1\right )

Set up a quadratic equation

\begin{array}{rcl}-50 & = & 1200 \tan \theta - 19.6\tan^{2} \theta -19.6 \\0 & = & 1200 \tan \theta - 19.6\tan^{2} \theta + 30.4\\0 & =&19.6\tan^{2} \theta - 1200 \tan \theta - 30.4\\0 & =&\tan^{2} \theta - 61.224 \tan \theta - 1.551\\\end{array}

Solve for θ

Use the quadratic formula.

tanθ = 61.249 or -0.025

θ = arctan(61.249) = 89.1° or

θ = arctan(-0.025) = -1.4°

3 0
3 years ago
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