Complete the equation of the line through (-6,-5)(−6,−5)(, minus, 6, comma, minus, 5, )and (-4,-4)(−4,−4)(, minus, 4, comma, min
alina1380 [7]
Answer:

Step-by-step explanation:
We have been given two points on a line
and
. We are asked to write an equation passing through these points.
We will write our equation in slope-intercept form of equation
, where,
m = Slope of line,
b = Initial value or the y-intercept.
Let us find slope of given line using slope formula.

Let point
and point
.



Now, we will substitute
and coordinates of point
in slope-intercept form of equation as:




Upon substituting
and
in slope-intercept form of equation, we will get our required equation as:

Therefore, our required equation would be
.
Answer:
i = 75.7°
h = 48.2°
Step-by-step explanation:
==>To find i, use the sine rule for finding angles: sin(A)/a = sin(B)/b
Where,
a = 7.2cm
sin(A) = i
b = 6.5cm
sin(B) = sin(61) = 0.8746
Thus:
sin(A)/7.2 = 0.8746/6.5
Multiply both sides by 7.2
sin(A) = (0.8746*7.2)/6.5
sin(A) = 0.969 (3 s.f)
A = i° = sin^-1(0.969) = 75.7 (3 s.f)
==>To find h, use the Cosine rule for angles:
Cos(C) = (a²+b²-c²)/2ab
cos(C) = h°, a = 4, b = 4.5, c = 3.5
a² = 16
b² = 20.25
c² = 12.25
cos(C) = (16+20.25-12.25)/(2*4*4.5)
cos(C) = 24/36
cos(C) = 0.667 (3 s.f)
C = h° = cos^-1(0.667) = 48.2° (3 s.f)
Divine the total number of the entire chart by the number of a single line or bar to give you the ratio in a bar or line chart. For example, if a bar or line represented 5 in a chart with a total of 30, you would divide 30 by 5. This would give you a result of 6. Therefore, the ratio would be 6:1.
Answer:
89.1° or -1.4°
Step-by-step explanation:
1. Location:
You are on the Mont-Saint-Jean escarpment, near the Belgian town of Waterloo.
The French troops are about 50 m below you and 1.2 km distant.
2. Finding the firing angle
Data:
R = 1200 m
u = 600 m/s
h = -50 m (the height of the target)
a = 9.8 m/s²
We have two conditions.
Horizontal distance
(1) 1200 = 600t cosθ
Vertical distance
(2) -50 = 600t sinθ - 4.9t²
Divide each side of (1) by 600cosθ.

Substitute (3) into (2)

Recall that
(5) sec²θ = 1/cos²θ = tan²θ + 1
Substitute (5) into (4)

Set up a quadratic equation

Solve for θ
Use the quadratic formula.
tanθ = 61.249 or -0.025
θ = arctan(61.249) = 89.1° or
θ = arctan(-0.025) = -1.4°