1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Delvig [45]
3 years ago
9

The world brand of rivet placement is 11209 rivets in 9 hours and belongs to J. Mair of Ireland. If another person places 11209

rivets in 10 hours, how long will it take both of them, if they work together, to place the 11209 rivets?
Mathematics
1 answer:
Ilya [14]3 years ago
5 0

Answer:

4.74 hours

Step-by-step explanation:

Given that both person have to place same number of rivets that is

11209

first person take 9 hours to complete the work

hence 1 hour work of 1st person is \frac{1}{9} of total work

second person takes 10 hours to complete the same work

hence 1 hour work of 2nd person is \frac{1}{10}

Now if both work together then

1 hour work of both person = \frac{1}{9} +\frac{1}{10} =\frac{19}{90}

thus working together they need \frac{90}{19} hours = 4.74 hours to complete the whole work which is placing 11209 rivets  

You might be interested in
When you subtract 76 by 8 and make it a pattern, then what rule can it be?
ludmilkaskok [199]

Answer:9.5

Step-by-step explanation:

5 0
2 years ago
Find k so that the distance from (–1, 1) to (2, k) is 5 units. k= k= *there are two solutions for 2*
dalvyx [7]

Answer:

k = -3

k =5

Step-by-step explanation:

d = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}\\d = 5\\(-1,1) =(x_1,y_1)\\(2,k)=(x_2,y_2)\\

5=\sqrt{\left(2-\left(-1\right)\right)^2+\left(k-1\right)^2}\\\\\mathrm{Square\:both\:sides}:\quad 25=k^2-2k+10\\25=k^2-2k+10\\\\\mathrm{Solve\:}\:25=k^2-2k+10:\\k^2-2k+10=25\\\\\mathrm{Subtract\:}25\mathrm{\:from\:both\:sides}\\k^2-2k+10-25=25-25\\k^2-2k-15=0\\\\\mathrm{Solve\:by\:factoring}\\\\\mathrm{Factor\:}k^2-2k-15:\quad \left(k+3\right)\left(k-5\right)\\\mathrm{Solve\:}\:k+3=0:\quad k=-3\\

\mathrm{Solve\:}\:k-5=0:\quad k=5\\\\k =5 , k=-3

7 0
3 years ago
Read 2 more answers
What is the value of n? ​
scoundrel [369]

Answer:

5?

Step-by-step explanation:

4 0
3 years ago
HELP WITH QUESTION 14 AND 15 IF I GET THEM RIG U WILL GIVE BRAINLIEST
Mila [183]

Answer:

333 meters per second

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
The daily cost of producing x high performance wheels for racing is given by the following​ function, where no more than 100 whe
algol [13]

Answer:

The production would be 25 wheels,

Lowest average cost is $ 123.75

Step-by-step explanation:

Given cost function,

C(x) = 0.09x^3 - 4.5x^2 + 180x

Where,

x = number of wheel,

So, the average cost per wheel,

A(x) = \frac{C(x)}{x}=\frac{0.09x^3-4.5x^2 + 180x}{x}=0.09x^2 - 4.5x + 180

Differentiating with respect to x,

A'(x) = 0.18x - 4.5

Again differentiating with respect to x,

A''(x) = 0.18

For maxima or minima,

A'(x) = 0

0.18x - 4.5 = 0

0.18x = 4.5

\implies x = \frac{4.5}{0.18}=25

For x = 25, A''(x) = positive,

i.e. A(x) is maximum at x = 25.

Hence, the production would be 25 wheels for the lowest average cost per​ wheel.

And, lowest average cost,

A(x) = 0.09(25)² - 4.5(25) + 180 = $ 123.75

5 0
3 years ago
Other questions:
  • What is the answer to this question?
    13·2 answers
  • Given f(x)=3^(x-2) and g(x)=f(3x)+4, write the function rule for function g and describe the types of transformations that occur
    6·2 answers
  • Please help me out!!!!!!!! :)
    9·2 answers
  • Please express the value of 72° in radians.
    8·1 answer
  • PLEASE HELP ME DO THIS
    6·1 answer
  • Help plz:)))I’ll mark u Brainliest
    5·1 answer
  • HELP PLEASE!!! ANSWERS WITH LINKS WILL BE DELETED AND REPORTED!!!
    14·2 answers
  • Pls help me with this question!!!!
    6·1 answer
  • How do I find a least common denominator? <br><br>​
    8·2 answers
  • A circle has a radius of 16 m. What is its circumference?
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!