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Delvig [45]
3 years ago
9

The world brand of rivet placement is 11209 rivets in 9 hours and belongs to J. Mair of Ireland. If another person places 11209

rivets in 10 hours, how long will it take both of them, if they work together, to place the 11209 rivets?
Mathematics
1 answer:
Ilya [14]3 years ago
5 0

Answer:

4.74 hours

Step-by-step explanation:

Given that both person have to place same number of rivets that is

11209

first person take 9 hours to complete the work

hence 1 hour work of 1st person is \frac{1}{9} of total work

second person takes 10 hours to complete the same work

hence 1 hour work of 2nd person is \frac{1}{10}

Now if both work together then

1 hour work of both person = \frac{1}{9} +\frac{1}{10} =\frac{19}{90}

thus working together they need \frac{90}{19} hours = 4.74 hours to complete the whole work which is placing 11209 rivets  

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ioda

Answer:

96

Step-by-step explanation:

3*6=18*2=36

6*10=60*2=120

10*3=30*2=60

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216

8 0
3 years ago
Read 2 more answers
Equation of a circle whose center is at (4,0) and radius is length 2/3
Masteriza [31]
We need (x-h)^2 + (y-k)^2 = r^2

h = 4, k = 0 and r = 2/3

Take it from here.
5 0
3 years ago
Linda's penny bank is 2/3 full. After she removes 80 pennies, it is 1/2 full. How many pennies can Linda's bank hold?
Ksju [112]
Let x = the total number of pennies her piggy bank can hold.
Then 2/3x = the number of pennies she started with
Then 2/3x - 80 = the number of pennies she has left after taking out 80 pennies.
Then 1/2x = the number of pennies she has left after taking out 80 pennies.
Build the equation.

2/3x - 80 = 1/2x

Subtract 1/2x from each side of the equation.

(2/3x - 80) - 1/2x = 1/2x - 1/2x

1/6x - 80 = 0

Add 80 to both sides of the equation.

(1/6x - 80) + 80 = 0 + 80

1/6x = 80

Divide both sides by 1/6.

(1/6x) / 1/6 = 80 / 1/6

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So, Linda's piggy bank can hold 480 pennies!

8 0
3 years ago
Which graph represents the solution set of the system of inequalities?
Novay_Z [31]
Answer:
(see image)
bottom right image

Explanation:
First try the origin (0,0) to rule out two of the graphs. 
3y ≥ x - 9 
3(0) ≥ (0) - 9 
3 ≥ - 9  yes 
3x + y > - 3 
3(0) + (0) > - 3
3 > - 3 yes 
so the origin should be in the shaded area of the graph, which rules out the top right and bottom left graphs. 
Now try a coordinate that is in the shaded area of one of the remaining graphs, but not in the other one. If it works, the graph is the one that has that point in the shaded region, and vice versa. 
Try point (4, 2)
3y ≥ x - 9 
3(2) ≥ (4) - 9
6 ≥  - 5 yes
3x + y > - 3 
3(4) + (2) > - 3
12 + 2 > - 3
14 > - 3 yes
So the graph is the bottom right one since (4, 2) is included in that shaded region.

4 0
3 years ago
A packet of vegetable seeds has a germination rate of
Doss [256]

N = number of seeds planted

P = probability of germination

K = number that germinated

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p(10) = (12 10) x 0.90^10 x 0.10^2

P(10) = 0.2310

8 0
2 years ago
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