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1 year ago

Does anybody know this?

Mathematics

1 answer:

dedylja [7]1 year ago

4 0

Answer:

here you go , all four completed, took me some time , hipe i was able to help you out tho

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Interest = $45.60, Rate = 2%, Time = 4 years<br> What’s the principal to the nearest cent

natita [175]

Answer:

$570

Step-by-step explanation:

I=PRT/100

I=$45.60,P=?,R=2%,T=4years

make P the subject of the formula

P=100I/RT

P=100x45.60/2x4

P=4560/8

P=$570

5 0

3 years ago

11. Reason Identify each solution as rational or

melamori03 [73]

Answer:

a. Rational; b. rational

Step-by-step explanation:

A rational number is the quotient of two integers.

a. ⁴/₇ + ⁻¹/₃

$\begin{array}{rcl}\dfrac{4}{7} + \dfrac{-1}{3} & = & \dfrac{12}{21} + \dfrac{-7}{21} \\\\& = & \dfrac{5}{21}\\\end{array}$

The solution is rational.

b. √4 ⅖

$\begin{array}{rcl}\sqrt{4} \, \dfrac{2}{5} & = & 2 \, \dfrac{2}{5}\\\\& = & \dfrac{22}{5}\\\end{array}$

The solution is rational.

7 0

3 years ago

If the statement, "If I am hungry, then I am not happy," is assumed to be true, is its negation, "If I am not hungry, then I mus

garik1379 [7]

The negation isn't always true, as you can be unhappy while also not being hungry.

3 0

2 years ago

3. Mike and Chris mowed lawns to earn money to go on a trip at the end of the month. Mike earned $20 for each lawn he mowed in h

Natali [406]

Answer:

x= The amount of lawns Mike mowed

y= The amount of lawns Chris Mowed

Equation 1: ($20+$15)(x+y)+$50=$500

Equation 2: ($20x)+($20xy)+$50=$500

3 0

3 years ago

Simplify: cos2x-cos4 all over sin2x + sin 4x

GrogVix [38]

Answer:

$\frac{\cos\left(2x\right)-\cos\left(4x\right)}{\sin\left(2x\right)+\sin\left(4x\right)}=\tan\left(x\right)$

Step-by-step explanation:

$\frac{\cos\left(2x\right)-\cos\left(4x\right)}{\sin\left(2x\right)+\sin\left(4x\right)}$

Apply formula:

$\cos\left(A\right)-\cos\left(B\right)=-2\cdot\sin\left(\frac{A+B}{2}\right)\cdot\sin\left(\frac{A-B}{2}\right)$ and

$\sin\left(A\right)+\sin\left(B\right)=2\cdot\sin\left(\frac{A+B}{2}\right)\cdot\sin\left(\frac{A-B}{2}\right)$

We get:

$=\frac{-2\cdot\sin\left(\frac{2x+4x}{2}\right)\cdot\sin\left(\frac{2x-4x}{2}\right)}{2\cdot\sin\left(\frac{2x+4x}{2}\right)\cdot\cos\left(\frac{2x-4x}{2}\right)}$

$=\frac{-\sin\left(\frac{2x-4x}{2}\right)}{\cos\left(\frac{2x-4x}{2}\right)}$

$=\frac{-\sin\left(\frac{-2x}{2}\right)}{\cos\left(\frac{-2x}{2}\right)}$

$=\frac{-\sin\left(-x\right)}{\cos\left(-x\right)}$

$=\frac{-\cdot-\sin\left(x\right)}{\cos\left(x\right)}$

$=\frac{\sin\left(x\right)}{\cos\left(x\right)}$

$=\tan\left(x\right)$

Hence final answer is

$\frac{\cos\left(2x\right)-\cos\left(4x\right)}{\sin\left(2x\right)+\sin\left(4x\right)}=\tan\left(x\right)$

6 0

2 years ago