All categories

3 years ago

5/3 plus 11/4 I NEED IT FAST!!

Mathematics

1 answer:

slega [8]3 years ago

6 0

The answer is 53/12=4 5/12

You might be interested in

Please can u answer these for me

ziro4ka [17]

18 . it's increasing by 5 every time so the next one after 23 is 28

4 0

3 years ago

Choose the equation and the slope of the line that passes trough (5,-3) and is parallel to the x-axis

lesya [120]

Answer:

y = -3

Step-by-step explanation:

Parallel to the x axis means that it is a horizontal line

It is of the form y =

Given the point ( 5, -3)

The y value is -3

y = -3

3 0

3 years ago

A culinary club earns $1190 from a dinner service. They sold 34 adult meals and 51 student meals. an adult meal costs twice as m

Murrr4er [49]

59 gdgdksgfjjjkkkkjjjjjjjjjjjjjjjj

5 0

3 years ago

Read 2 more answers

Hal has a steel barrel with a diameter of 6 feet that can be filled to a depth of 4.6 feet with oil. What is the volume of the b

scoray [572]

Answer:

129.996 cubic feet

Step-by-step explanation:

Assuming that the barrel is a perfect cylinder, we can use the formula to find the volume:

$\pi(r)^2(h)$

First, we have to find the radius, which is:

D = 2r

So the radius is 3 feet, since it is half of the diameter. Then, we plug in the values.

$3.14(3)^2(4.6)$

Now, we solve. Exponents are first...

3.14(9)(4.6)

Now multiply left to right.

28.26(4.6)

129.996 cubic feet

Therefore, the barrel can hold 129.996 cubic feet of oil. Hope this helps you!

3 0

3 years ago

use the formulas for lowering powers to rewrite the expression in terms of the first power of cosine cos^4

Firdavs [7]

The expression cos⁴ θ in terms of the first power of cosine is <u>[ 3 + 2cos 2θ + cos 4θ]/8.</u>

The power-reducing formula, for cosine, is,

cos² θ = (1/2)[1 + cos 2θ].

In the question, we are asked to use the formulas for lowering powers to rewrite the expression in terms of the first power of cosine cos⁴ θ.

We can do it as follows:

cos⁴ θ

= (cos² θ)²

= {(1/2)[1 + cos 2θ]}²

= (1/4)[1 + cos 2θ]²

= (1/4)(1 + 2cos 2θ + cos² 2θ] {Using (a + b)² = a² + 2ab + b²}

= 1/4 + (1/2)cos 2θ + (1/4)(cos ² 2θ)

= 1/4 + (1/2)cos 2θ + (1/4)(1/2)[1 + cos 4θ]

= 1/4 + cos 2θ/4 + 1/8 + cos 4θ/8

= 3/8 + cos 2θ/4 + cos 4θ/8

= [ 3 + 2cos 2θ + cos 4θ]/8.

Thus, the expression cos⁴ θ in terms of the first power of cosine is <u>[ 3 + 2cos 2θ + cos 4θ]/8</u>.

Learn more about reducing trigonometric powers at

brainly.com/question/15202536

#SPJ4

5 0

2 years ago