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3 years ago

Please help! Please break down what equation or process I need to do to get the answer as well :/

Mathematics

1 answer:

nirvana33 [79]3 years ago

8 0

Check the picture below.

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What is the square root of 8374

Rainbow [258]

91.5095623419 is the answer

7 0

4 years ago

HELP ASAP WILL MARK BRAINLIEST IF YOU DONT KNOW DONT ANSWER

astraxan [27]

Answer:

x = 13

48 = 5x - 17

+17 + 17

5x = 65

x = 13

8 0

3 years ago

The legs of an isosceles triangle are 0.3 foot less than twice the base. The perimeter of the triangle is 4.9 feet.

Sidana [21]

I hope this helps you

base = b

length= 2b-0.3

Perimeter=b+2b-0.3+2b-0.3

4.9=5b-0.6

5b=5.5

b=1.1

length =2×1.1-0.3

length=2.2-0.3

length=1.9

5 0

3 years ago

Read 2 more answers

Prove algebraically that the straight line with equation x=2y+5 is a tangent to the circle with equation x^2+y^2=5

zmey [24]

Differentiate both sides of the equation of the circle with respect to $x$ , treating $y=y(x)$ as a function of $x$ :

$x^2+y^2=5\implies2x+2y\dfrac{\mathrm dy}{\mathrm dx}=0\implies\dfrac{\mathrm dy}{\mathrm dx}=-\dfrac xy$

This gives the slope of any line tangent to the circle at the point $(x,y)$ .

Rewriting the given line in slope-intercept form tells us its slope is

$x=2y+5\implies y=\dfrac12x-\dfrac52\implies\mathrm{slope}=\dfrac12$

In order for this line to be tangent to the circle, it must intersect the circle at the point $(x,y)$ such that

$-\dfrac xy=\dfrac12\implies y=-2x$

In the equation of the circle, we have

$x^2+(-2x)^2=5x^2=5\implies x=\pm1\implies y=\mp2$

If $x=-1$ , then $-1=2y+5\implies y=-3\neq2$ , so we omit this case.

If $x=1$ , then $1=2y+5\implies y=-2$ , as expected. Therefore $x=2y+5$ is a tangent line to the circle $x^2+y^2=5$ at the point (1, -2).

7 0

4 years ago

Read 2 more answers

What is the solution of the equation? A. –5, 11 B. 5 C. 11 D. –11

rjkz [21]

Answer:

The solution is -5 or 11

Step-by-step explanation:

We are given the equation;

$4(3-x)^\frac{4}{3}-5=59$

We are supposed to solve the equation;

Taking 5 to the other side;

$4(3-x)^\frac{4}{3}=59+5$

$4(3-x)^\frac{4}{3}=64$

Dividing both sides by 4

$(3-x)^\frac{4}{3}=\frac{64}{4}$

$(3-x)^\frac{4}{3}=16$

We can cube both sides;

$((3-x)^\frac{4}{3})^3=16^3$

$(3-x)^4=4096$

Then we can get the fourth root on both sides of the equation;

$\sqrt[4]{ (3-x)^4} =\sqrt[4]{4096}$

We get;

$3-x=+8 or -8$

Solving for x

$3-x=8 and 3-x=-8$

Therefore;

$x=-5 or 11$

Therefore, the solution is -5 or 11

3 0

4 years ago