Jamil has already 6 3/4 cups of butter.
He need 12. SO in order to get the needed butter, we subtract 6 3/4 to 12.
= 12 - 6 3/4
= 11 4/4 - 6 3/4
= 5 1/4
So Jamil needs 5 1/4 cups of butter to achieve the 12 cups.
Hi this is the graph from desmos!
Answer:
m<PTR = 140°
Step-by-step explanation:
First, find the value of x. To find the value of x, derive an equation which you'd use in solving for x.
m<PTQ = (x + 28)°
m<RTS = (2x + 16)°
m<PTQ = m<RTS (vertical opposite angles are congruent)
Therefore:
x + 28 = 2x + 16
Solve for x. Combine like terms
28 - 16 = 2x - x
12 = x
x = 12
Find m<PTQ
m<PTQ = (x + 28)
plug in the value of x
m<PTQ = 12 + 28 = 40°
m<PTR + m<PTQ = 180° (supplementary angles)
m<PTR + 40° = 180° (substitution)
m<PTR = 180 - 40 (subtracting 40 from each side)
m<PTR = 140°
Answer:
l:9
p:16.4
Step-by-step explanation:
l x w = A
A÷w=l
37.8÷4.4=9
2l+2w=P
18+8.4=16.4
keeping in mind that radius is half the diameter, we know this cone has a diameter of 2 inches, so it has a radius of 1 inch, kinda small really for ice-cream, but anyhow.
![\textit{volume of a cone}\\\\ V=\cfrac{\pi r^2 h}{3}~~ \begin{cases} r=radius\\ h=height\\[-0.5em] \hrulefill\\ r=1\\ h=6 \end{cases}\implies V=\cfrac{\pi (1)^26}{3}\implies V=2\pi \implies \underset{\textit{rounded up}}{V\approx 6}](https://tex.z-dn.net/?f=%5Ctextit%7Bvolume%20of%20a%20cone%7D%5C%5C%5C%5C%20V%3D%5Ccfrac%7B%5Cpi%20r%5E2%20h%7D%7B3%7D~~%20%5Cbegin%7Bcases%7D%20r%3Dradius%5C%5C%20h%3Dheight%5C%5C%5B-0.5em%5D%20%5Chrulefill%5C%5C%20r%3D1%5C%5C%20h%3D6%20%5Cend%7Bcases%7D%5Cimplies%20V%3D%5Ccfrac%7B%5Cpi%20%281%29%5E26%7D%7B3%7D%5Cimplies%20V%3D2%5Cpi%20%5Cimplies%20%5Cunderset%7B%5Ctextit%7Brounded%20up%7D%7D%7BV%5Capprox%206%7D)
