Part I
The weight of the truck without cargo is 22150+11300= 33450 pound
The weight of the cargo is given as
and altogether with the weight of the truck, the sum must not exceed 75500
The inequality is given
Part II
Hence, the maximum weight allowed for the cargo is 42050 pounds
Answer:
none of them
Step-by-step explanation:
they all have x-values that lead to two different y-values.
A)
Withdraws--5.23, -5.22, and -7.89
Deposits-34.98, 51.02, and 51.22
(Rational numbers include integers, whole numbers, decimals that don't repeat or go on forever, and fractions)
B)
-7.89, -5.23, -5.22, 34.98, 51.02, 51.22
(Negatives are less than 0, so when the negative gets bigger, it means that the number is becoming less, so the opposite of positive numbers)
C)
98+34.98+51.02+51.22= 235.22
235.22- 5.22-5.23-7.89= 216.88
216.88 is the answer
(since withdraws are subtracting from the total, you want to add up all of the positive numbers so the deposits plus the amount she had in the beginning, and then subtract the withdraws)
Hope this helps!
