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Elanso [62]
3 years ago
13

HELP!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Mathematics
1 answer:
adelina 88 [10]3 years ago
3 0
The answer is 2.041*10 to the 6th power
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I’m so confused <br> I feel like I’ve tried everything <br> Please help
Cerrena [4.2K]
130 - 40 = 90 (because you need to have soil to have flowers to grow)




90/6 = 15

So 15 flowers she can buy
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3 years ago
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Solve the following equations: (a) x^11=13 mod 35 (b) x^5=3 mod 64
tino4ka555 [31]

a.

x^{11}=13\pmod{35}\implies\begin{cases}x^{11}\equiv13\equiv3\pmod5\\x^{11}\equiv13\equiv6\pmod7\end{cases}

By Fermat's little theorem, we have

x^{11}\equiv (x^5)^2x\equiv x^3\equiv3\pmod5

x^{11}\equiv x^7x^4\equiv x^5\equiv6\pmod 7

5 and 7 are both prime, so \varphi(5)=4 and \varphi(7)=6. By Euler's theorem, we get

x^4\equiv1\pmod5\implies x\equiv3^{-1}\equiv2\pmod5

x^6\equiv1\pmod7\impleis x\equiv6^{-1}\equiv6\pmod7

Now we can use the Chinese remainder theorem to solve for x. Start with

x=2\cdot7+5\cdot6

  • Taken mod 5, the second term vanishes and 14\equiv4\pmod5. Multiply by the inverse of 4 mod 5 (4), then by 2.

x=2\cdot7\cdot4\cdot2+5\cdot6

  • Taken mod 7, the first term vanishes and 30\equiv2\pmod7. Multiply by the inverse of 2 mod 7 (4), then by 6.

x=2\cdot7\cdot4\cdot2+5\cdot6\cdot4\cdot6

\implies x\equiv832\pmod{5\cdot7}\implies\boxed{x\equiv27\pmod{35}}

b.

x^5\equiv3\pmod{64}

We have \varphi(64)=32, so by Euler's theorem,

x^{32}\equiv1\pmod{64}

Now, raising both sides of the original congruence to the power of 6 gives

x^{30}\equiv3^6\equiv729\equiv25\pmod{64}

Then multiplying both sides by x^2 gives

x^{32}\equiv25x^2\equiv1\pmod{64}

so that x^2 is the inverse of 25 mod 64. To find this inverse, solve for y in 25y\equiv1\pmod{64}. Using the Euclidean algorithm, we have

64 = 2*25 + 14

25 = 1*14 + 11

14 = 1*11 + 3

11 = 3*3 + 2

3 = 1*2 + 1

=> 1 = 9*64 - 23*25

so that (-23)\cdot25\equiv1\pmod{64}\implies y=25^{-1}\equiv-23\equiv41\pmod{64}.

So we know

25x^2\equiv1\pmod{64}\implies x^2\equiv41\pmod{64}

Squaring both sides of this gives

x^4\equiv1681\equiv17\pmod{64}

and multiplying both sides by x tells us

x^5\equiv17x\equiv3\pmod{64}

Use the Euclidean algorithm to solve for x.

64 = 3*17 + 13

17 = 1*13 + 4

13 = 3*4 + 1

=> 1 = 4*64 - 15*17

so that (-15)\cdot17\equiv1\pmod{64}\implies17^{-1}\equiv-15\equiv49\pmod{64}, and so x\equiv147\pmod{64}\implies\boxed{x\equiv19\pmod{64}}

5 0
3 years ago
How do you use a scientific calculator?
egoroff_w [7]
Try to start by reading the manual it came with. If it didn't come with a manual, then your teacher in school will teach you how to use it for specific commands. Otherwise it's just like using a regular calculator but with the ability to do more things, what do you need to know on it?
8 0
3 years ago
Among two supplementary angles, the measure of the larger angle is 44°
zhuklara [117]

Answer:

68° and 112°

Step-by-step explanation:

Supplementary angles sum to 180°

let the smaller angle be x then the larger angle is x + 44 , then

x + x + 44 = 180 , that is

2x + 44 = 180 ( subtract 44 from both sides )

2x = 136 ( divide both sides by 2 )

x = 68

Smaller angle = 68° and

larger angle = x + 44 = 68 + 44 = 112°

6 0
2 years ago
Help me pls this is urgent ;&gt;
postnew [5]

Answer:

\frac{ |a + x| }{2}  -  \frac{ |a - x| }{2}  \\  \\  =  \frac{ | - 2 - 6| }{2}  -  \frac{ | - 2 + 6| }{2}  \\  \\  =  \frac{ | - 8| }{2}  -  \frac{ |4| }{2}  \\  \\  =  \frac{8}{2}  -  \frac{4}{2}  \\  \\  = 4 - 2 = 2

5 0
2 years ago
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