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givi [52]
2 years ago
9

What is the volume of this figure? Enter your answer in the box. m³

Mathematics
1 answer:
IRINA_888 [86]2 years ago
7 0

Answer:

Im pretty sure the answer is 497; i did the math :)

Step-by-step explanation:

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Suppose the demand for a certain item is given by:
Marysya12 [62]

Answer:

a. D'(p) = -10p - 6

b. There is a decrease of 96 units of demand for each dollar increase

Step-by-step explanation:

The demand function is:

D(p) = - 5p^2-6p+400

(a) The derivate of the demand function with respect to price gives us the rate of change of demand:

\frac{dD(p)}{dp}=D'(p) = -10p-6

(b) When p = $9, the rate of change of demand is:

D'(9) = -10*9-6\\D'(9) = -96\ \frac{units}{\$}

This means that, when p = $9,  there is a decrease of 96 units of demand for each dollar increase.

6 0
3 years ago
On the coordinate plane below , quadrilateral 1 has been transformed to form quadrilateral 2?
Cerrena [4.2K]

Answer:

1 and 5

Step-by-step explanation:

because the math

3 0
3 years ago
F(x) = x + 1)?
natali 33 [55]

Answer:

the gragh that represents the step function is...

4 0
3 years ago
36. Mrs. Smith will install a ceiling fan in cach room of
otez555 [7]

Answer:

4353.5

Step-by-step explanation:

2 bedrooms and a living room, sorry I forgot to add that in, there's also 3 small windows and a large one

3 rooms

552*3 = 1656

small window = 539.50 * 3 = 1618.50

Large window - 2*539.50 = 1079

1656+1618.5+1079=4353.5

5 0
3 years ago
We wish to give a 90% confidence interval for the mean value of a normally distributed random variable. We obtain a simple rando
coldgirl [10]

Answer: (9.27025,\ 11.12975)

Step-by-step explanation:

Given : Sample size : n= 9

Degree of freedom = df =n-1 =8

Sample mean : \overline{x}=10.2

sample standard deviation : s= 1.5

Significance level ; \alpha= 1-0.90=0.10

Since population standard deviation is not given , so we use t- test.

Using t-distribution table , we have

Critical value = t_{\alpha/2, df}=t_{0.05 , 8}=1.8595

Confidence interval for the population mean :

\overline{x}\pm t_{\alpha/2, df}\dfrac{s}{\sqrt{n}}

90% confidence interval for the mean value will be :

10.2\pm (1.8595)\dfrac{1.5}{\sqrt{9}}

10.2\pm (1.8595)\dfrac{1.5}{3}

10.2\pm (1.8595)(0.5)

10.2\pm (0.92975)

(10.2-0.92975,\ 10.2+0.92975)

(9.27025,\ 11.12975)

Hence, the 90% confidence interval for the mean value= (9.27025,\ 11.12975)

6 0
3 years ago
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