we have been given that in ΔFGH, the measure of ∠H=90°, GF = 53, HG = 28, and FH = 45. We are asked to find the ratio that represents the sine of ∠G.
First of all, we will draw a right triangle using our given information.
We know that sine relates opposite side of right triangle with hypotenuse.
We can see from the attachment that opposite side to angle G is FH and hypotenuse is GF.
Therefore, the ratio 
represents the sine of ∠G.
From the text you can derive the following equations:
(1) A = bh/2 = 8
(2) and h = b+6
Fill in h in (1):
b(b+6)/2 = 8 => b^2 + 6b = 16 with the quadratic formula or simply trying some values for b you can find b=2, so h=8.
Answer:
5/2
Step-by-step explanation:
Y(2)-Y(1)/ X(2)-X(1)
(27-2)/(1-(-9)
25/10
simplified=5/2
Answer:
3(4x+8) or 4(3x+6) or 12(x+2)
Step-by-step explanation:
Answer:
Step-by-step explanation:
triangles that are the same are congruent
A) no
B) no
C) yes
D) yes
E) no
