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3 years ago

How do you solve for the central area of a polygon?

1 answer:

5 0

Getting the central area of a polygon is not possible. Probably the question refers to the central angle. In a a regular polygon, getting the central angle is that you need to use the formula.

Central Angle of a polygon = 360 degrees / number of sides of a polygon.
Why 360 degrees? Because, a circle has a total of 360 degrees. And a circle is a polygon with no sides.

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Multiplying fractions by whole numbers 7x4/8 equal

asambeis [7]

28/8 or 7/2 is the answer to that

3 0

3 years ago

Read 2 more answers

A recent survey found that 86% of employees plan to devote at least some work time to follow games during the NCAA Men's Basketb

trasher [3.6K]

Answer:

4.18% probability that less than 80% of this sample will devote work time to follow games

Step-by-step explanation:

Normal probability distribution

When the distribution is normal, we use the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

For a proportion p in a sample of size n, the sampling distribution of the sample proportion will be approximately normal with mean $\mu = p$ and standard deviation $s = \sqrt{\frac{p(1-p)}{n}}$

In this question, we have that:

$p = 0.86, n = 100$

$\mu = 0.86, s = \sqrt{\frac{0.86*0.14}{100}} = 0.0347$

What is the probability that less than 80% of this sample will devote work time to follow games?

This is the pvalue of Z when X = 0.8. So

$Z = \frac{X - \mu}{\sigma}$

By the Central Limit Theorem

$Z = \frac{X - \mu}{s}$

$Z = \frac{0.8 - 0.86}{0.0347}$

$Z = -1.73$

$Z = -1.73$ has a pvalue of 0.0418

4.18% probability that less than 80% of this sample will devote work time to follow games

7 0

3 years ago

How do you write 0.663 as a percentage

BigorU [14]

The answer is 66.3%

Always move the decimal over 2 to the right to get a percent. If it's from a percent, then move it to the left 2 spaces.

4 0

2 years ago

Read 2 more answers

The diameter of a planet is about 10,652 mi. The diameter of the planet's moon is about 25% of the planet. What percent of the v

alekssr [168]

Answer:

$2\%$

Step-by-step explanation:

we know that

If two figures are similar, then the ratio of its volumes is equal to the scale factor elevated to the cube

Let

z-----> the scale factor

x----> the volume of the planet's moon

y---> the volume of the planet

$z^{3}=\frac{x}{y}$

In this problem we have

$z=0.25$

elevated to the cube

$z^{3}=0.25^{3}=0.015625$

Find the percent

$0.015625*100=1.56\%$

Round to the nearest whole number

$1.56\%=2\%$

5 0

3 years ago

Which side lengths form a right triangle?

Natalija [7]

Answer:

this is kinda confusing..So ill just answer the first question.

<h3>Explanation: The Pythagorean Theorem gives us a2 + b2 = c2 for a right triangle, where c is the hypotenuse and a and b are the smaller sides.</h3>

hope it helps.

5 0

3 years ago