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3 years ago

An information system can enhance core competencies by

Computers and Technology

1 answer:

Nutka1998 [239]3 years ago

4 0

Answer:

An information system can enhance core competencies by: encouraging the sharing of knowledge across business units.

Explanation:

Hope this helps you ! please mark me brainless

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What is the name of the the world cell of the internet?

irga5000 [103]

Answer:

mobile web is the the world cell of internet

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3 years ago

Which of these is an example of an open source software

AURORKA [14]

Answer:

Thunderbird

Explanation:

When we talk about open source software, we are talking about software that is free to download and its source code repository is made available and public to its users. Open source code can be modified and distributed with the users’ rights if they want to. Thunderbird is an example of open source developed by the Mozilla foundation. All known web browsers like Chromium and Safari are open source apart from Internet Explorer. Internet Explorer has remained closed source for a long time now.

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4 years ago

Renée’s job entails using a company laptop to constantly open other peoples’ workbooks, sorting the data, importing a new sheet

nevsk [136]

she should leave and go somewhere else for a mminute to cool and then come backa nd close tabs.

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3 years ago

The Gramm-Leach-Bliley Act contains a rule that ensures security and confidentiality of customer information, protects against a

ValentinkaMS [17]

Answer:

b. The Safeguards Rule

Explanation:

According to a different source, these are the options that come with this question:

a. The Information Assurance Rule

b. The Safeguards Rule

c. The Safety Rule

d. The Guardian Rule

This rule is called the Safeguards Rule, and it comes from the Gramm–Leach–Bliley Act (GLBA), also known as the Financial Services Modernization Act of 1999. This is an act of Congress signed by President Bill Clinton that removed barriers among banking companies, securities companies and insurance companies. This meant that organizations such as commercial banks, investment banks, securities firms, and insurance companies were able to consolidate.

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4 years ago

Read 2 more answers

A person gets 13 cards of a deck. Let us call for simplicity the types of cards by 1,2,3,4. In How many ways can we choose 13 ca

natima [27]

Answer:

There are 5,598,527,220 ways to choose 5 cards of type 1, 4 cards of type 2, 2 cards of type 3 and 2 cards of type 4 from a set of 13 cards.

Explanation:

The crucial point of this problem is to understand the possible ways of choosing any type of card from the 13-card deck.

This is a problem of combination since the order of choosing them does not matter here, that is, the important fact is the number of cards of type 1, 2, 3 or 4 we can get, no matter the order that they appear after choosing them.

So, the question for each type of card that we need to answer here is, how many ways are there of choosing 5 cards of type 1, 4 cards of type 2, 2 cards of type 3 and 2 are of type 4 from the deck of 13 cards?

The mathematical formula for combinations is $\\ \frac{n!}{(n-k)!k!}$ , where n is the total of elements available and k is the size of a selection of k elements from which we can choose from the total n.

Then,

Choosing 5 cards of type 1 from a 13-card deck:

$\frac{n!}{(n-k)!k!} = \frac{13!}{(13-5)!5!} = \frac{13*12*11*10*9*8!}{8!*5!} = \frac{13*12*11*10*9}{5*4*3*2*1} = 1,287$ , since $\\ \frac{8!}{8!} = 1$ .

Choosing 4 cards of type 2 from a 13-card deck:

$\\ \frac{n!}{(n-k)!k!} = \frac{13!}{(13-4)!4!} = \frac{13*12*11*10*9!}{9!4!} = \frac{13*12*11*10}{4!}= 715$ , since $\\ \frac{9!}{9!} = 1$ .

Choosing 2 cards of type 3 from a 13-card deck:

$\\ \frac{n!}{(n-k)!k!} =\frac{13!}{(13-2)!2!} = \frac{13*12*11!}{11!2!} = \frac{13*12}{2!} = 78$ , since $\\ \frac{11!}{11!}=1$ .

Choosing 2 cards of type 4 from a 13-card deck:

It is the same answer of the previous result, since

$\\ \frac{n!}{(n-k)!k!} = \frac{13!}{(13-2)!2!} = 78$ .

We still need to make use of the Multiplication Principle to get the final result, that is, the ways of having 5 cards of type 1, 4 cards of type 2, 2 cards of type 3 and 2 cards of type 4 is the multiplication of each case already obtained.

So, the answer about how many ways can we choose 13 cards so that there are 5 of type 1, there are 4 of type 2, there are 2 of type 3 and there are 2 of type 4 is:

1287 * 715 * 78 * 78 = 5,598,527,220 ways of doing that (or almost 6 thousand million ways).

In other words, there are 1287 ways of choosing 5 cards of type 1 from a set of 13 cards, 715 ways of choosing 4 cards of type 2 from a set of 13 cards and 78 ways of choosing 2 cards of type 3 and 2 cards of type 4, respectively, but having all these events at once is the multiplication of all them.

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4 years ago