A smart way of moving money from one personal banking account directly to another account is called EFT or electric fund transfer. There is a maximum clearance time of 24 hours for transfer. The most widely-used program is Direct Deposit, in which payroll is deposited straight into an employee's bank account initiated through an electronic terminal, including credit card, Therefore, the following<span> statement regarding EFT is false?</span>
<span>1. </span><span>EFT still requires the endorsement of a check </span>
Answer:
Hot site.
Explanation:
It seems to be a specific and completely designed functionality inside the sites which assist disaster recovery, in which the organization may travel directly during a disaster as well as continue operations.
- It may be described as such a recovery site that is repeatedly fully operational.
- It enables the corporation to resume normal corporate processes during a disaster, within such a limited period cycle.
The protocol that should be implemented is that one needs to enable hosts on the network to find the IP address.
<h3>What is IP address?</h3>
It should be noted that IP address simply means a unique address that defines a device on the internet.
In this case, the protocol that should be implemented is that one needs to enable hosts on the network to find the IP address.
Learn more about IP address on:
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Answer:
Explanation:
#include <iostream>
using namespace std;
int costdays(int);
int costhrs(int,int);
int main()
{
int dd,hh,mm,tmph,tmpd,tmpm=0;
int pcost,mcost=0;
cout<<"Enter Parking time" << endl;
cout<<"Hours: ";
cin>>hh;
cout<<"Minutes: ";
cin>>mm;
if (mm>60)
{
tmph=mm/60;
hh+=tmph;
mm-=(tmph*60);
}
if (hh>24)
{
tmpd=hh/24;
dd+=tmpd;
hh-=(tmpd*24);
}
if ((hh>4)&&(mm>0))
{
pcost+=costdays(1);
}
else
{
mcost=costhrs(hh,mm);
}
cout<<"Total time: ";
if (dd>0)
{
cout<<dd<<"days ";
pcost+=costdays(dd);
}
pcost+=mcost;
cout<<hh<<"h "<<mm<<"mins"<<endl;
cout<<"Total Cost :"<<pcost<<"Won";
return 0;
}
int costdays(int dd)
{
return(dd*25000);
}
int costhrs(int hh,int mm)
{
int tmpm, tmp=0;
tmp=(hh*6)*1000;
tmp+=(mm/10)*1000;
tmpm=mm-((mm/10)*10);
if (tmpm>0)
{
tmp+=1000;
}
return(tmp);
}
A or b i think hope it helps good luck and i hope it helps
