4 years ago

I suck at math...

Mathematics

1 answer:

Katen [24]4 years ago

5 0

It is the second option

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Given that <img src="https://tex.z-dn.net/?f=z%3Dx%2Biy" id="TexFormula1" title="z=x+iy" alt="z=x+iy" align="absmiddle" class="l

Mnenie [13.5K]

Answer:

$z= 5-2i$

Step-by-step explanation:

Start replacing!

$(x+iy) + 4i (x-iy) = -3+18i \\ x+iy +4ix -4i^2 y = -3 + 18i \\\\x + i (4x+y) +4y = -3 + 18i\\x+4y + (4x+y) i = -3 + 18i$

Now two complex numbers are equal if both the real and imaginary parts are equal, which gives you the system of equation $\left \{x+4y=-3} \atop {4x+y=18} \right.$

Pick any method to solve it and you'll get $x=5, y= -2$

6 0

3 years ago

3. Which equation can be represented by the graph shown below?

DanielleElmas [232]

Answer:

y = -1/3x + 12/5

Step-by-step explanation:

6 0

3 years ago

Plz answer this question quickly

garri49 [273]

The answer is HC, HT, HH, CC, CT, CH, TC, TT, TH

7 0

4 years ago

X + 3y = −1<br> 2x + 2y = 6

hram777 [196]

$\left\{\begin{array}{ccc}x+3y=-1\\2x+2y=6&|divide\ both\ sides\ by\ (-2)\end{array}\right\\\\\underline{+\left\{\begin{array}{ccc}x+3y=-1\\-x-y=-3\end{array}\right}\\.\ \ \ \ \ \ \ \ \ 2y=-4\ \ \ \ |divide\ both\ sides\ by\ 2\\.\ \ \ \ \ \ \ \ \ \fbox{y=-2}\\\\subtitute\ the\ value\ of\ y\ to\ the\ equation\ x+3y=-1\\\\x+3\cdot(-2)=-1\\x-6=-1\ \ \ \ |add\ 6\ to\ both\ sides\\\fbox{x=5}\\\\Answer:\boxed{x=5\ and\ y=-2}$

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4 years ago

Last question!!!!!!!<br><br> Is Number 10 correct?

natali 33 [55]

Number 10 for what? i don't see anything

3 0

4 years ago