(120x)^1/2 see attached photo for steps
Answer:
2
Step-by-step explanation:
Given g(x) = sin(x)-1/cos2(x), we are to find the limit if the function g(x) as g(x) tends to π/2
Substituting π/2 into the function
lim x-->π/2 sin(x)-1/cos 2(x)
= sin(π/2) - 1/cos(2)(π/2)
= 1 - 1/cosπ
= 1- 1/-1
= 1 -(-1)
= 1+1
= 2
Hence the limit of the function h(x) = sin(x)-1/cos2(x) as x--> π/2 is 2
Midpoint formula:
x, y = (x2+x1/2), (y2+y1/2)
x, y= (3+8/2), (4-4/2)
x, y= (5.5), (0)
Therefor the midpoint is (5.5, 0)
Hope I helped :)
Answer:
y = -2x - 5
Step-by-step explanation:
2y = x - 3
y = 1/2x - 3/2
gradient = 1/2
perpendicular gradient = negative reciprocal = -2
y = -2x + c
(-3) = -2(-1) + c
-3 = 2 + c
-5 = c
