-6y + 11x = -36....multiply by 4
-4y + 7x = -24....multiply by -6
-----------------
-24y + 44x = - 144 (result of multiplying by 4)
24y - 42x = 144 (result of multiplying by -6)
----------------add
2x = 0
x = 0
-4y + 7x = -24
-4y + 7(0) = -24
-4y = -24
y = -24/-4
y = 6
solution is (0,6)
A total of 3.75 x 10⁷ transcription factors are phosphorylated in response to the first messenger. The number of transcription factors phosphorylated if one copy of the d enzyme is inactivated is 3.7499 x 10⁷.
<h3>What is phosphorylation?</h3>
Phosphorylation is a posttranslational modification that suffers proteins during the activation of a singling pathway.
Phosphorylation is capable of activating and/or deactivating specific signaling pathways.
In this case, phosphorylation activates a molecular cascade involving the progressive phosphorylation of different substrates.
In this case, 3.75 x 10⁷ transcription factors are phosphorylated in response to the first messenger (100 x 100 x 75 x 50 = 3.75 x 10⁷), whereas the number of transcription factors phosphorylated if one copy of d enzyme is inactivated is 3.7499 x 10⁷ (3.75 x 10⁷ - 50).
Learn more about phosphorylation here:
brainly.com/question/19578076
By conservation of momentum,
(900 kg) (15.0 m/s) i + (750 kg) (20.0 m/s) j = (900 kg + 750 kg) v
where v is the velocity vector of the combined cars. Solve for v :
(13,500 i + 15,000 j) kg•m/s = (1650 kg) v
v ≈ (8.18 i + 9.09 j) m/s
Then the direction of v relative to East is θ such that
tan(θ) ≈ 9.09/8.18 ⇒ θ ≈ 48.0°
so the wreckages would move at approximately 48.0° north of east.
Answer:
area = Iw
Explanation:
area = lw
where
l = length
w = width
Therefore,
The area of the shaded region = area of the big rectangle - area of the small rectangle
Therefore,
area of the big rectangle = (x+10)(2x+5) = 2x² + 5x + 20x + 50 = 2x² + 25x + 50
area of the small rectangle = (x+1)(x+1) = x² + x + x + 1 = x² + 2x + 1
area of the shaded region = 2x² + 25x + 50 - ( x² + 2x + 1)
area of the shaded region = 2x² + 25x + 50 - x² - 2x - 1
area of the shaded region = x² - 23x - 49
