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kramer
3 years ago
9

Given triangle ABC with vertices A(16,0), B(9,2), and C(2,0).

Mathematics
1 answer:
Margaret [11]3 years ago
4 0
Given:

Triangle Point coordinates or vertices:
A(16,0)
B(9,2)
C(2,0)

Required:

Side with slope -2/7

Solution:

To know which side has the slope required, we need to calculate the slope of each paired point by the two-point slope formula:

m = (y2-y1)/(x2-x1)

We first try points A and B.

m1 = (2-0)/(9-16)

m1 = -2/7

Thus, the side with the slope -2/7 is side AB.
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maria [59]

Answer:

Step-by-step explanation:

2) When x = 6

x - 2y = 8

6 - 2y = 8

    -2y = 8 - 6

    -2y = 2

       y = 2/-2

     y = -1

Yes, (6, -1) lies on the line.

3) No, (-2 , -3) is not on the line

4) (-2 , -3) is not a solution to this equation because it does not lie on the line.

7 0
3 years ago
In right triangle JFK sin(52)= cos(5x-2). What is the measure of the smallest angle in the triangle?
jeyben [28]

Answer:

48°

Step-by-step explanation:

Given the trigonometry equation

sin(52)= cos(5x-2)...1

According to the quadrant:

Sin(θ) = cos(90-θ)

Sin52 = cos(90-52)

Sin52 = cos48... 2

Substituting 2 into 1:

Cos48 = cos(5x-2)

48 = 5x-2

5x = 48+2

5x = 50

x = 10°

The smallest of the angle will be angle 5x-2 = 5(10)-2

= 50-2

= 48°

7 0
3 years ago
Simplify the rational expression:<br> 5y+5/2 ÷ 25y-20/40y²-32y
NNADVOKAT [17]

Step-by-step explanation:

Your problem → 5y+5/2 / 25y-20/40y^2-32y

5y+5/2÷25y-20/40y^2-32y

=5⋅y+5/2÷25×y-20/40×y^2-32×y

=5y+5/2÷25×y-20/40×y^2-32y

=5y+5/2×1/25×y-20/40×y^2-32y

=5y+y/10-20/40×y^2-32y

=5y+y/10-y^2/2-32y

=5y×10+y-y^2×5-32y×10 ÷ 10

=50y+y-5y2-320y ÷ 10

= -269y-5y^2 / 10

4 0
3 years ago
In a right triangle, the hypotenuse has endpoints P(–3, 2) and Q(1, –3). On a coordinate plane, line P Q has points (negative 3,
mrs_skeptik [129]

Answer:

The length of PR is 5 units

Step-by-step explanation:

Here, we want to calculate the length of PR

Since PQ is the hypotenuse, it means that the right-angle would be between lines PR and RQ

Also, since R is on the third quadrant, then its coordinates are (-x,-y)

To get the coordinates of R since we know that we need a right angle, we drop a straight vertical line through P and a straight horizontal line through Q

What this mean is that the coordinates of R will take the x-coordinate of the point P and the y-coordinate of the point Q

Hence, we have that the coordinates of the point R is (-3,-3)

Now, we want to calculate the length of PR

PR will be the distance between the points P and R

Mathematically, to get this, we use the distance formula

That will be;

√(y2-y1)^2 + (x2-x1)^2

Thus, we have

√(2-(-3)^2 + (-3-(-3))^2

= √5^2 + 0^2

= √25 = 5 units

4 0
3 years ago
Read 2 more answers
Evaluate<br><br> x = -3.75<br><br> 4x + 12 - 8x + 23 =
yanalaym [24]

Answer:

u have Isolate the variable by dividing each side by factors that don't contain the variable. and the correct answer is x=2.7442371

Step-by-step explanation:

Brainliest plz

4 0
3 years ago
Read 2 more answers
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