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S_A_V [24]
3 years ago
15

What are the two ways to determine if something is a function

Mathematics
2 answers:
Darina [25.2K]3 years ago
7 0

Answer:

If a vertical line crosses the relation on the graph only once in all locations, the relation is a function. However, if a vertical line crosses the relation more than once, the relation is not a function. Using the vertical line test, all lines except for vertical lines are functions.

Step-by-step explanation:

elena-s [515]3 years ago
5 0

Answer:

If a vertical line crosses the relation on the graph only once in all locations, the relation is a function.

However, if a vertical line crosses the relation more than once, the relation is not a function.

Step-by-step explanation:

Using the vertical line test, all lines except for vertical lines are functions.

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nadya68 [22]

Answer:

11

Step-by-step explanation:

g(x) = 2x + 7

Put x as 2 and evaluate.

g(2) = 2(2) + 7

Multiply.

g(2) = 4 + 7

Add the terms.

g(2) = 11

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How many coefficients are in the expression 5x³ - 2n² + 6x - 4?
ikadub [295]

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Find the 4 angles and the measure of are abd
Svetradugi [14.3K]

Answer:

Angle 1 = 80 (by definition)

Angle 3 = 180 - 80 = 100

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Also, Angle 2 = 40 (by definition)

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6 0
4 years ago
3. The Food Marketing Institute shows that 17% of households spend more than $100 per week on groceries. Assume the population p
damaskus [11]

Answer:

A)sample proportion = 0.17,  the sampling distribution of p can be calculated/approximated with normal distribution of sample proportion = 0.17 and standard error/deviation = 0.013281

B) 0.869

C)0.9668

Step-by-step explanation:

A) p ( proportion of population that spends more than $100 per week) = 0.17

sample size (n)= 800

the sample proportion of p = 0.17

standard error of p = \sqrt{\frac{p(1-p)}{n} } = 0.013281

the sampling distribution of p can be calculated/approximated with

normal distribution of sample proportion = 0.17 and standard error/deviation = 0.013281

B) probability that the sample proportion will be +-0.02 of the population proportion

= p (0.17 - 0.02 ≤ P ≤ 0.17 + 0.02 ) = p( 0.15 ≤ P ≤ 0.19)

z value corresponding to P

Z = \frac{P - p}{standard deviation}

at P = 0.15

Z =  (0.15 - 0.17) / 0.013281 = = -1.51

at P = 0.19

z = ( 0.19 - 0.17) / 0.013281 = 1.51

therefore the required probability will be

p( -1.5 ≤ z ≤ 1.5 ) = p(z ≤ 1.51 ) - p(z ≤ -1.51 )

                           = 0.9345 - 0.0655 = 0.869

C) for a sample (n ) = 1600

standard deviation/ error = 0.009391 (applying the equation for calculating standard error as seen in part A above)

therefore the required probability after applying

z = \frac{P-p}{standard deviation} at p = 0.15 and p = 0.19

p ( -2.13 ≤ z ≤ 2.13 ) = p( z ≤ 2.13 ) - p( z ≤ -2.13 )

                               = 0.9834 - 0.0166 = 0.9668

7 0
3 years ago
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