The domain is the x-axis, and the range is the y values. The domain would be
-∞ to ∞. And the range is 2 to ∞.
So if the shapes are similar, they have to have a number multiple from to get the other triangle. If you divide 63 by 42, you get 1.5. Then you have to divide 54 by 1.5 to get G and that would be 36.
Answer:
(e) csc x − cot x − ln(1 + cos x) + C
(c) 0
Step-by-step explanation:
(e) ∫ (1 + sin x) / (1 + cos x) dx
Split the integral.
∫ 1 / (1 + cos x) dx + ∫ sin x / (1 + cos x) dx
Multiply top and bottom of first integral by the conjugate, 1 − cos x.
∫ (1 − cos x) / (1 − cos²x) dx + ∫ sin x / (1 + cos x) dx
Pythagorean identity.
∫ (1 − cos x) / (sin²x) dx + ∫ sin x / (1 + cos x) dx
Divide.
∫ (csc²x − cot x csc x) dx + ∫ sin x / (1 + cos x) dx
Integrate.
csc x − cot x − ln(1 + cos x) + C
(c) ∫₋₇⁷ erf(x) dx
= ∫₋₇⁰ erf(x) dx + ∫₀⁷ erf(x) dx
The error function is odd (erf(-x) = -erf(x)), so:
= -∫₀⁷ erf(x) dx + ∫₀⁷ erf(x) dx
= 0
Answer:
2.16 * (10^-5).
Step-by-step explanation:
5 = -log H+
5 = log (1 / H+)
1/ H+ = 10^5
H+ = 10^-5
In a similar fashion the other brand has H+ of 10^-4.5.
So the difference in hydrogen ion concentration = 10^(-4.5) - 10^(-5)
= 2.16 * (10^-5).
Answer:
The surface area of the pyramid is 466,137 squared cubits
Step-by-step explanation:
This is simply asking us to find the surface area of the square based pyramid with the given dimensions.
The first thing we need to know is the principle for finding the surface area of such pyramidal shapes. To get the surface area of a pyramid, we will have to add the base area to the area of the side faces ( lateral area)
The base area of the square based pyramid, will be the same as the area of a square which is = 453 cubits X 453 cubits =
The lateral area has already been given to us as 260,928 squared cubits.
The surface area of the pyramid is 260,928 + 205209 = 466137 squared cubits
Hence, the surface area of the pyramid is 466137 squared cubits