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ValentinkaMS [17]
3 years ago
7

What is the area of this polygon?

Mathematics
1 answer:
olchik [2.2K]3 years ago
6 0

Answer:

I'm pretty sure the answer is 34.5

Step-by-step explanation:

the small triangle on the left area is 1.5

the rectangle formed area is 18

the triangle on top area is 9

I believe the triangle's area on the right is 6

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Here’s the pic help please answer I’ll give brainliest !! It’s for a test
Fudgin [204]
A= -2

b=0

hope this helps
8 0
3 years ago
I need help with this please!
Gennadij [26K]

Answer:

5ft

Step-by-step explanation:

perimeter=l+l+w+w

l=12

p=24+2w

34-24=10

10/2=5

8 0
2 years ago
A random sample of 20 recent weddings in a country yielded a mean wedding cost of $ 26,388.67. Assume that recent wedding costs
Makovka662 [10]

Answer:

a) 95% confidence interval for the mean​cost, μ​, of all recent weddings in this country = (22,550.95, 30,226.40)

.The​ 95% confidence interval is from $22,550.95 to $30,226.40.

b) For the interpretation of the result, option D is correct.

We can be​ 95% confident that the mean​ cost, μ​, of all recent weddings in this country is somewhere within the confidence interval.

c) Option B is correct.

The population mean may or may not lie in this​ interval, but we can be​ 95% confident that it does.

Step-by-step explanation:

Sample size = 20

Sample Mean = $26,388.67

Sample Standard deviation = $8200

Confidence Interval for the population mean is basically an interval of range of values where the true population mean can be found with a certain level of confidence.

Mathematically,

Confidence Interval = (Sample mean) ± (Margin of error)

Sample Mean = 26,388.67

Margin of Error is the width of the confidence interval about the mean.

It is given mathematically as,

Margin of Error = (Critical value) × (standard Error of the mean)

Critical value will be obtained using the t-distribution. This is because there is no information provided for the population mean and standard deviation.

To find the critical value from the t-tables, we first find the degree of freedom and the significance level.

Degree of freedom = df = n - 1 = 20 - 1 = 19.

Significance level for 95% confidence interval

(100% - 95%)/2 = 2.5% = 0.025

t (0.025, 19) = 2.086 (from the t-tables)

Standard error of the mean = σₓ = (σ/√n)

σ = standard deviation of the sample = 8200

n = sample size = 20

σₓ = (8200/√20) = 1833.6

99% Confidence Interval = (Sample mean) ± [(Critical value) × (standard Error of the mean)]

CI = 26,388.67 ± (2.093 × 1833.6)

CI = 26,388.67 ± 3,837.7248

99% CI = (22,550.9452, 30,226.3948)

99% Confidence interval = (22,550.95, 30,226.40)

a) 95% confidence interval for the mean​cost, μ​, of all recent weddings in this country = (22,550.95, 30,226.40)

.The​ 95% confidence interval is from $22,550.95 to $30,226.40.

b) The interpretation of the confidence interval obtained, just as explained above is that we can be​ 95% confident that the mean​ cost, μ​,of all recent weddings in this country is somewhere within the confidence interval

c) A further explanation would be that the population mean may or may not lie in this​ interval, but we can be​ 95% confident that it does.

Hope this Helps!!!

4 0
3 years ago
What is the quotient?<br><br> <img src="https://tex.z-dn.net/?f=X-3%5Csqrt%7Bx%7D%204X%5E2%2B3X%2B2" id="TexFormula1" title="X-3
romanna [79]
You have to factor out the 3
7 0
3 years ago
On a certain hot​ summer's day, 581 people used the public swimming pool. The daily prices are $1.50 for children and $2.50 for
Tanya [424]

Answer:

A = 219

C = 362

Step-by-step explanation:

Given,

581 = C + A

and

$1090.50 = 1.5C + 2.5A

solve 1st for A

A =581 - C

substute into 2nd

1090.50 = 1.5C + 2.5(581 - C)

solve for C

1090.50 = 1.5C + 1452.50 - 2.5C

1090.50 = -C + 1452.50

1090.50 - 1452.50 = -C

-362 = -C

C = 362

then

581 = C + A

581 = 362 + A

219 = A

A = 219

8 0
3 years ago
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