Brainliest for help! Sketch a graph of the function y =sin(x) + 2
1 answer:
Answer:
The parent sine graph has a range of -1 ≤ y ≤ 1
It crosses the x-axis x = 0° ± 180°n
The maximum points occur when x = 90° ± 360°n and y = 1
The minimum points occur when x = 270° ± 360°n and y = -1
The sketch the graph of function we simply move the graph of
up 2 units.
So this means it will have a range of 1 ≤ y ≤ 3
It no longer crosses the x-axis.
The maximum points occur when x = 90° ± 360°n and y = 3
The minimum points occur when x = 270° ± 360°n and y = 1
<u>Attached diagram</u>
The parent function is shown in grey (dashed line)
The function is shown in red.
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Answer:
Step-by-step explanation:
From the graph attached,
Coordinates of the vertices are,
Q(1, 3), R(3, -3), S(0, -2) and T(-2, 1)
Following the rule of translation by 3 units to the right and 2 units down
(x, y) → (x+3, y-2)
Q(1, 3) → Q''(4, 1)
R(3, -3) → R"(6, -5)
S(0, -2) → S"(3, -4)
T(-2, 1) → T"(1, -1)
Following rule (rotation of a point by 180° about the origin) will give the image points,
(x, y) → (-x, -y)
Q"(4, 1) → Q'(-4, -1)
R"(6, -5) → R'(-6, 5)
S"(3, -4) → S'(-3, 4)
T"(1, -1) → T'(-1, 1)