we have
(a+b)(3a-b)(2a+7b)
step 1
Solve
apply distributive property
(a+b)(3a-b)=3a^2-ab-3ab-b^2=3a^2-4ab-b^2
step 2
Multiply (3a^2-4ab-b^2) by (2a+7b)
6a^3+21a^2b-8a^2b-28ab^2-2ab^2-7b^3=6a^3+13a^2b-30ab^2-7b^3
answer is
<h2>6a^3+13a^2b-30ab^2-7b^3</h2>
Answer:
Step-by-step explanation:
Given
Required
Find all product of real values that satisfy the equation
Cross multiply:
Subtract 7 from both sides
Reorder
Multiply through by -1
The above represents a quadratic equation and as such could take either of the following conditions.
(1) No real roots:
This possibility does not apply in this case as such, would not be considered.
(2) One real root
This is true if
For a quadratic equation
By comparison with
Substitute these values in
Add 56 to both sides
Divide through by 4
Take square roots
Hence, the possible values of r are:
or 
and the product is:
Answer:
Step-by-step explanation:
Hope this helps!
Answer:
No similarity and no scale factor (I could be wrong)
Step-by-step explanation:
Don't worry, no links :)
You would see if they are similar if they have similar sides. so if there is an equal ratio, to both, they are similar. Sometimes they may not look similar until you rotate them. So for the following, you can see that if E were on the bottom, it would look like the triangle with N and M on the bottom you can ensure this to look at the ratios of each side. To find the scale factor, it depends on which way you are going. are you going from GEF to MNL or MNL to GEF? To me, it doesn't look like there is a scale factor, but I could be wrong.
