So average=(total of scores)/(number of tests)
needs at least average of 70
at least is represented as greater than or equal to or the sign (<u>></u>)
70<u>></u>(total)/(number oftests)
since we have 3 tests, we have to have 3 scores so
70<u>></u>(x+y+z)/3
he scored 85 and 60
70<u>></u>(x+85+60)/3 (doesn't matter which to subsitute)
70<u>></u>(x+145)/3
multiply obht sides by 3
210<u>></u>x+145
subtract 145 from both sides
65<u>></u>x
he needs to get at leas 65 on his third test
Answer:
4
step by step if she has 7 cups and already put in 3
7-3=4
Answer:
C
Step-by-step explanation:
To find (g ○ f)(x), substitute x = f(x) into g(x) , that is
g(2x - 5)
= 3(2x - 5) + 4
= 6x - 15 + 4
= 6x - 11 → C
B
Step-by-step explanation:
2000$ is far from 30$ so it is b
The image is missing, we have attached the image.
Answer:
The of getting an even number in first and an odd number second is
.
Step-by-step explanation:
Given,
Total number of outcomes = 36
We have to find the probability of rolling an even number first and an odd number second.
Solution,
Firstly we will find out the possible outcomes;

So the total number of outcomes = 9
Now according to the formula of probability, which is;

Now on putting the values, we get;
P(of getting an even number in first and an odd number second)=
Hence The of getting an even number in first and an odd number second is
.