Answer:
Step-by-step explanation:
Consider triangle ACD. This triangle is isosceles triangle, because AD = DC. Angles adjacent to the base AC are congruent abgles, so
The sum of the measures of all interiror angles in the triangle is always 
then
Angles ADC and BDC are supplementary angles (add up to 
), then
Consider triangle BCD. This triangle is isosceles triangle because BC = DC. Angles adjacent to the base BD are congruent abgles, so
The sum of the measures of all interiror angles in the triangle is always then
Answer:
Step-by-step explanation:
hello :
15r² – 6r – 3 = -2r
15r² – 6r – 3 +2r =0
15r²-4r -3 =0
delta =b² -4ac a=15 b=-4 c=-3
delta =(-4)² - 4(15)(-3)=196 = 14²
r1 = (-b - √delta ) /2a = (4-14)/30 = -10/30 = -2/6 = -1/3
r2 = (-b + √delta ) /2a = (4+14)/30 = 18/30 = 3/5
Matt could do 2 boxes of 908. 1,816 divided by 2 is 908.
(x + 11) *squared* +(y-12) *squared* = 49
<h3 /><h3>V. Cylinder = π . r² . h</h3>
12,704.44 = 3.14 × r² × 14
12,704.44 = 3.14 × 14 × r²
12,704.44 = 43.96 × r²
r² = 12,704.44/43.96
r² = 289
r = √289
r = 17
<h3>#CMIIW</h3>
