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Leona [35]
2 years ago
6

99 in./s = mi/day Converting rates for 7th grade math can’t seem to figure it out

Mathematics
1 answer:
Alexxx [7]2 years ago
6 0
I think the answer is A. Hope this helps!
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Last week, Jason ran 26.1 miles. He wants to run further this week. He plans to run 2.4 miles to the park, four times around the
nordsb [41]

Answer:

Greater than (>)

Step-by-step explanation:

Last week, Jason ran 26.1 miles.

He wants to run further this week.

<u>Distance Run this week</u>

  • 2.4 miles to the park,
  • Four times around the park= 4p (if distance around the park is p miles)
  • 2.4 miles back from the park.

Total Distance this week =2.4+4p+2.4

Since his distance this week is going to be greater than the total distance covered last week (26.1 miles), we then have:

Total Distance covered this week > Total Distance Last week

2.4+4p+2.4>26.1

Jason should use the greater than inequality sign.

4 0
3 years ago
Read 2 more answers
What is the surface area of a cylinder with base
Alisiya [41]

Answer:

138.23

Step-by-step explanation:

2πrh+2πr^2=2·π·2·9+2·π·2^2

3 0
2 years ago
An agricultural company called Phatsima Pty. Ltd. owns an rectangular fuel tank that measures 75 cm by 65 cm by 30 cm.
GaryK [48]
I believe that A is the answer. We can solve this by multiplying 75cm, 65cm and 30cm together. This would give us 146,250.00ml. We can then divide 146,250.00 by 1000 to receive 146.25. We then divide 146.25 by 2 to calculate how many litres there are in half a tank. This would result in 73.125. After that, we multiple 73.125 by the cost of the fuel, which is R20.35. We then receive R 1,480.09375, which can be rounded to R 1,480.10
3 0
1 year ago
Translate this phrase into an algebraic expression.
Anna007 [38]

Answer:

73-2n

Step-by-step explanation:

5 0
3 years ago
Suppose you solved a second-order equation by rewriting it as a system and found two scalar solutions: y = e^5x and z = e^2x. Th
xenn [34]

Answer:

The solutions are linearly independent because the Wronskian is not equal to 0 for all x.

The value of the Wronskian is \bold{W=-3e^{7x}}

Step-by-step explanation:

We can calculate the Wronskian using the fundamental solutions that we are provided and their corresponding the derivatives, since the Wroskian is defined as the following determinant.

W = \left|\begin{array}{cc}y&z\\y'&z'\end{array}\right|

Thus replacing the functions of the exercise we get:

W = \left|\begin{array}{cc}e^{5x}&e^{2x}\\5e^{5x}&2e^{2x}\end{array}\right|

Working with the determinant we get

W = 2e^{7x}-5e^{7x}\\W=-3e^{7x}

Thus we have found that the Wronskian is not 0, so the solutions are linearly independent.

3 0
3 years ago
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