The remainder theorem says that dividing a polynomial by
leaves a remainder of
. Here,
, then
.
What is the answer to this?
1 answer:
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Answer:
No, it isn't.
Step-by-step explanation:
We have and let
be the subset of
of all points on the line
We need to find if is a subspace of the vector space
.
In all the possibilities for own subspace of the vector space
are :
itself.
- The vector
- All lines in
)
We know that is the subset of
of all points on the line
If we look at the equation, the point doesn't verify it because :
Which is an absurd. Therefore, doesn't contain the origin (and
is a line in
). Finally, it can't be a vector space of