y = 9ln(x)
<span>y' = 9x^-1 =9/x</span>
y'' = -9x^-2 =-9/x^2
curvature k = |y''| / (1 + (y')^2)^(3/2)
<span>= |-9/x^2| / (1 + (9/x)^2)^(3/2)
= (9/x^2) / (1 + 81/x^2)^(3/2)
= (9/x^2) / [(1/x^3) (x^2 + 81)^(3/2)]
= 9x(x^2 + 81)^(-3/2).
To maximize the curvature, </span>
we find where k' = 0. <span>
k' = 9 * (x^2 + 81)^(-3/2) + 9x * -3x(x^2 + 81)^(-5/2)
...= 9(x^2 + 81)^(-5/2) [(x^2 + 81) - 3x^2]
...= 9(81 - 2x^2)/(x^2 + 81)^(5/2)
Setting k' = 0 yields x = ±9/√2.
Since k' < 0 for x < -9/√2 and k' > 0 for x >
-9/√2 (and less than 9/√2),
we have a minimum at x = -9/√2.
Since k' > 0 for x < 9/√2 (and greater than 9/√2) and
k' < 0 for x > 9/√2,
we have a maximum at x = 9/√2. </span>
x=9/√2=6.36
<span>y=9 ln(x)=9ln(6.36)=16.66</span>
the
answer is
(x,y)=(6.36,16.66)
Answer:
Step-by-step explanation:
2 * L + 2 * W = 68
2*L = 2* 9x = 9x + 9x
2*W = 2*8x = 8x + 8x
Since the perimeter is 68
9x + 9x + 8x + 8x = 68
Answer:
The answer is
<h2>
</h2>
Step-by-step explanation:
Equation of a line is y = mx + c
where
m is the slope
c is the y intercept
To find the equation we must first find the slope of the line.
So the slope of the line using points (-3, 7) and (9,-1) is
<h3>
</h3>
Now we use the formula
<h3>y - y1 = m(x - x1)</h3>
where
m is the slope
( x1 , y1) is any of the points given
So the equation of the line using point
( - 3 , 7) and slope - 2/3 is
<h3>
</h3>
We have the final answer as
<h3>
</h3>
Hope this helps you
For solving this we need the change in distance and the change in time. You said that the change in time is 1.8 seconds and the change in distance is 3.6 meters. ( This is assuming it started at 0 meters and started at 0 seconds )
Since the starting was 0,0 we can toss them out as they add no value. Now since speed is labeled (in this case) m/s, we divide how many meters it traveled over how many seconds it took to travel it.
3.6 / 1.8 = 2
The average speed of the cart is 2 m/s
Answer:
1 pound
Step-by-step explanation:
