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luda_lava [24]
3 years ago
5

Forks come in packages of 10 and spoons come in packages of 8.jayrod wants to have the same number of forks and spoons and does

not to spend more than he has to.how many packages of forks ans spoons does he need to buy so that he does not have any left over?
Mathematics
1 answer:
uysha [10]3 years ago
7 0
5 packages of spoons and and 4 packages of forks
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Jan has $245.50 to spend on home repairs. The repairman charges $75 for the initial visit and $35 per hour or any part of an hou
Murrr4er [49]

Answer:

4

Step-by-step explanation:

4 0
3 years ago
PLEASE HELP ME ASAAAAAPPPPPPPPPPPP PLEASE HELP ME FAST What is 5 x 2/3 ? A) 3 1/3 B) 3 2/5 C) 5 2/3 D) 10/15
katrin2010 [14]

Answer:

A) 3 1/3

Step-by-step explanation:

5 x 2 = 10

10/3= 3 with a remainder of 1. That gives you 3 1/3

5 0
3 years ago
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x = c1 cos(t) + c2 sin(t) is a two-parameter family of solutions of the second-order DE x'' + x = 0. Find a solution of the seco
igomit [66]

Answer:

x=-cos(t)+2sin(t)

Step-by-step explanation:

The problem is very simple, since they give us the solution from the start. However I will show you how they came to that solution:

A differential equation of the form:

a_n y^n +a_n_-_1y^{n-1}+...+a_1y'+a_oy=0

Will have a characteristic equation of the form:

a_n r^n +a_n_-_1r^{n-1}+...+a_1r+a_o=0

Where solutions r_1,r_2...,r_n are the roots from which the general solution can be found.

For real roots the solution is given by:

y(t)=c_1e^{r_1t} +c_2e^{r_2t}

For real repeated roots the solution is given by:

y(t)=c_1e^{rt} +c_2te^{rt}

For complex roots the solution is given by:

y(t)=c_1e^{\lambda t} cos(\mu t)+c_2e^{\lambda t} sin(\mu t)

Where:

r_1_,_2=\lambda \pm \mu i

Let's find the solution for x''+x=0 using the previous information:

The characteristic equation is:

r^{2} +1=0

So, the roots are given by:

r_1_,_2=0\pm \sqrt{-1} =\pm i

Therefore, the solution is:

x(t)=c_1cos(t)+c_2sin(t)

As you can see, is the same solution provided by the problem.

Moving on, let's find the derivative of x(t) in order to find the constants c_1 and c_2:

x'(t)=-c_1sin(t)+c_2cos(t)

Evaluating the initial conditions:

x(0)=-1\\\\-1=c_1cos(0)+c_2sin(0)\\\\-1=c_1

And

x'(0)=2\\\\2=-c_1sin(0)+c_2cos(0)\\\\2=c_2

Now we have found the value of the constants, the solution of the second-order IVP is:

x=-cos(t)+2sin(t)

3 0
3 years ago
Brianna has 4 pink bracelets. One third of all her bracelets are pink. How many braclets does Brianna have?
liq [111]
Brianna has 12 braclets
3 0
3 years ago
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Which symbol will make the number sentence -5 -- 5 true? <br> A =<br> b
Wittaler [7]

Answer: b

Step-by-step explanation:

8 0
3 years ago
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