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2 years ago

A golf ball has been hit off of the tee at an angle of elevation of 30 degrees and an initial velocity of 160 ft/sec.

SAT

1 answer:

Ede4ka [16]2 years ago

4 0

The golf ball follows a parabolic path, and it is modeled by a quadratic function

The maximum height of the golf ball is 99.47 feet

<h3>How to determine the maximum height of the ball?</h3>

The given parameters are:

Angle of elevation = 30 degrees
Initial velocity, u = 160 ft/sec

The maximum height of the ball is calculated using:

$H_{max} = \frac{u^2\sin^2(\theta)}{2g}$

Where:

g = 32.17 ft/sec^2

So, we have:

$H_{max} = \frac{160^2 * \sin^2(30)}{2 * 32.17}$

Evaluate

$H_{max} = 99.47$

Hence, the maximum height of the golf ball is 99.47 feet

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1 year ago

PLS HELP!!!! Select all the sequences of transformations that create a new congruent figure.

eduard

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