Question

A golf ball has been hit off of the tee at an angle of elevation of 30 degrees and an initial velocity of 160 ft/sec.

Answer 1

The golf ball follows a parabolic path, and it is modeled by a quadratic function

The maximum height of the golf ball is 99.47 feet

How to determine the maximum height of the ball?

The given parameters are:

• Angle of elevation = 30 degrees
• Initial velocity, u = 160 ft/sec

The maximum height of the ball is calculated using:

$H_{max} = \frac{u^2\sin^2(\theta)}{2g}$

Where:

g = 32.17 ft/sec^2

So, we have:

$H_{max} = \frac{160^2 * \sin^2(30)}{2 * 32.17}$

Evaluate

$H_{max} = 99.47$

Hence, the maximum height of the golf ball is 99.47 feet

Read more about maximum height at:

brainly.com/question/12446886