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balandron [24]
2 years ago
15

Solve the equation on the interval [0,2π).

Mathematics
1 answer:
Olegator [25]2 years ago
5 0

Answer:

π/2, 2π/3, 3π/2, 4π/3.

Step-by-step explanation:

8cos^2x+4cosx=0

4cosx(2cosx + 1) = 0

so cosx = 0, -1/2.

Therfore

When cos x = 0:

x = π/2, 3π/2

When cos x = -1/2:

x = 2π/3, 4π/3.

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Two angles in a triangle have measures of 62 and 15.
Radda [10]

Answer:

A) 103

Step-by-step explanation:

x + 62 + 15 = 180

x + 77 = 180

x = 103

8 0
3 years ago
Read 2 more answers
Simplify. 5x2 – 8x + 4x2 + 10x
Andru [333]

Answer:

10-8x+8+10x

18+2x

2(9+x)

3 0
3 years ago
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What are the values of x, y, and z in this system of equations?
scZoUnD [109]

Answer:

{x,y,z}={5,−3,3}

Step-by-step explanation:

  [1]    2x + 4y + z = 1

  [2]    x - 2y - 3z = 2

  [3]    x + y - z = -1

// Solve equation [3] for the variable  y  

 [3]    y = -x + z - 1

// Plug this in for variable  y  in equation [1]

  [1]    2x + 4•(-x +z -1) + z = 1

  [1]    -2x + 5z = 5

// Plug this in for variable  y  in equation [2]

  [2]    x - 2•(-x +z -1) - 3z = 2

  [2]    3x - 5z = 0

// Solve equation [2] for the variable  x  

 [2]    3x = 5z

 [2]    x = 5z/3

// Plug this in for variable  x  in equation [1]

  [1]    -2•(5z/3) + 5z = 5

  [1]    5z/3 = 5

  [1]    5z = 15

// Solve equation [1] for the variable  z  

  [1]    5z = 15

  [1]    z = 3

// By now we know this much :

   x = 5z/3

   y = -x+z-1

   z = 3

// Use the  z  value to solve for  x  

   x = (5/3)(3) = 5

// Use the  x  and  z  values to solve for  y  

 y = -(5)+(3)-1 = -3

Solution :

{x,y,z} = {5,-3,3}

5 0
3 years ago
H(a) = a^2 + 3a; Find h(-10)
Colt1911 [192]
H(-10)=70
because when you input -10 in for each a, it will equal 70
6 0
3 years ago
Give an example of undefined term and defined term in geometry
vovangra [49]
<span>These are undefined terms:1.plane2.point3.line.
These are defined </span><span>terms: 1.ray 2.union of sets 3.space 4.subset 5.set 6.proper subset 7.opposite</span><span><span>
</span></span>
4 0
4 years ago
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