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balandron [24]
2 years ago
15

Solve the equation on the interval [0,2π).

Mathematics
1 answer:
Olegator [25]2 years ago
5 0

Answer:

π/2, 2π/3, 3π/2, 4π/3.

Step-by-step explanation:

8cos^2x+4cosx=0

4cosx(2cosx + 1) = 0

so cosx = 0, -1/2.

Therfore

When cos x = 0:

x = π/2, 3π/2

When cos x = -1/2:

x = 2π/3, 4π/3.

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