<span>erry starts rowing at 2 pm from the west end of the lake, and Tao starts rowing from the east end of the lake at 2:05 pm.
------
Terry DATA:
rate = 60 meter/min ; time = x min ; distance = r*t = 60x meters
-----
Tao DATA:
rate = 40 meter/min ; time = x-5 min ; distance = r*t = 40(x-5) meters
--------------------------
If they always row directly towards each other at what time will the two meet?
------
Equation:
dist + dist = 2000 meters
60x + 40(x-5) = 2000
20x = 1800
x = 90 minutes
---</span>
Given that the ship was traveling for 4 mph faster heading west than south then let the speed of the ship heading south be x mph, the speed of the ship heading west will be (x+4) mph
the distance is given by:
distance=speed*time
distance heading south was:
x*4=4x miles
distance heading west was:
5(x+4)=5x+20
thus the total distance will be given by:
4x+(5x+20)=191
9x+20=191
9x=191-20
9x=171
x=171/9
x=19 mph
the speed the ship used to travel west was:
x+4
=19+4
=21 mph
First of all, you must find out how many miles it takes to go 4 hours and 8 hours.
112 ÷ 4 = 28 miles per hour
112 ÷ 8 = 14 miles per hour
So, going downstream will take 28 miles per hour and going in still water will take 14 miles per hour.
Answer:
h = a/4
Step-by-step explanation:
h = a/4 has already been solved for h; there is nothing left to do here.