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Andreyy89
2 years ago
13

Please help me with this trigonometry question. Brainliest available.

Mathematics
1 answer:
faltersainse [42]2 years ago
5 0
Considering the angle a by cosine rule
11^2 =7 ^2 +15^2 - 2(7)(15)cos(a)
When you do the maths,
Cos(a) =153/210 =0.729
a= cos inverse of 0.729
a=43 degrees


Considering angle b
7^2=15^2 +11^2 -2(11)(15) cos(b)
This will result in cos(b) =297/330=0.9
b= cos inverse of 0.9 = 25.8 degrees


Considering angle c
15^2=7^2 +11^2 - 2(11)(7) cos(c)
Cos(c) will be = -55/154 = -0.357
c= cos inverse of -0.357=110.9

Comparing the angles a,b and c,
C is the largest size in the triangle with an angle of 110.9 degrees

Am I right please ??
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4 0
4 years ago
Simplify and explain your answer 4/7+2/5(1/5+1/10)
muminat
\frac{4}{7}+\frac{2}{5}\cdot(\frac{1}{5}+\frac{1}{10})=\frac{4}{7}+\frac{2}{5}\cdot(\frac{2}{10}+\frac{1}{10})=\frac{4}{7}+\frac{2}{5}\cdot\frac{3}{10}=\frac{4}{7}+\frac{1}{5}\cdot\frac{3}{5}\\\\=\frac{4}{7}+\frac{6}{25}=\frac{4\cdot25}{7\cdot25}+\frac{6\cdot7}{25\cdot7}=\frac{100}{175}+\frac{42}{175}=\frac{142}{175}
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