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4 years ago

2/3x-5=21 (2/3 is a fraction_

2 answers:

8 0

You will distribute -5 to 21, making it positive
2/3x=26
you would then distribute 2/3 to 26 leaving us with
x=26/1(3/2)
X=13(3)
x=39

pochemuha4 years ago

5 0

2/3 x - 5 = 21
2/3 x = 21 + 5 = 26
x = 26 / 2/3 = 26 * 3 /2 = 78/2 = 39

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How would u do this and can u explain

Amanda [17]

M=2-(-6)/(-1)-(-2)=8
Y=8x+b
-6=8*(-2)+b
-6=-16+b
B=16-6=10
Y=8x+10

I hope my answer is help to you

4 0

3 years ago

the height h(t) of a trianle is increasing at 2.5 cm/min, while it's area A(t) is also increasing at 4.7 cm2/min. at what rate i

nekit [7.7K]

Answer:

The base of the triangle decreases at a rate of 2.262 centimeters per minute.

Step-by-step explanation:

From Geometry we understand that area of triangle is determined by the following expression:

$A = \frac{1}{2}\cdot b\cdot h$ (Eq. 1)

Where:

$A$ - Area of the triangle, measured in square centimeters.

$b$ - Base of the triangle, measured in centimeters.

$h$ - Height of the triangle, measured in centimeters.

By Differential Calculus we deduce an expression for the rate of change of the area in time:

$\frac{dA}{dt} = \frac{1}{2}\cdot \frac{db}{dt}\cdot h + \frac{1}{2}\cdot b \cdot \frac{dh}{dt}$ (Eq. 2)

Where:

$\frac{dA}{dt}$ - Rate of change of area in time, measured in square centimeters per minute.

$\frac{db}{dt}$ - Rate of change of base in time, measured in centimeters per minute.

$\frac{dh}{dt}$ - Rate of change of height in time, measured in centimeters per minute.

Now we clear the rate of change of base in time within (Eq, 2):

$\frac{1}{2}\cdot\frac{db}{dt}\cdot h = \frac{dA}{dt}-\frac{1}{2}\cdot b\cdot \frac{dh}{dt}$

$\frac{db}{dt} = \frac{2}{h}\cdot \frac{dA}{dt} -\frac{b}{h}\cdot \frac{dh}{dt}$ (Eq. 3)

The base of the triangle can be found clearing respective variable within (Eq. 1):

$b = \frac{2\cdot A}{h}$

If we know that $A = 130\,cm^{2}$ , $h = 15\,cm$ , $\frac{dh}{dt} = 2.5\,\frac{cm}{min}$ and $\frac{dA}{dt} = 4.7\,\frac{cm^{2}}{min}$ , the rate of change of the base of the triangle in time is:

$b = \frac{2\cdot (130\,cm^{2})}{15\,cm}$

$b = 17.333\,cm$

$\frac{db}{dt} = \left(\frac{2}{15\,cm}\right)\cdot \left(4.7\,\frac{cm^{2}}{min} \right) -\left(\frac{17.333\,cm}{15\,cm} \right)\cdot \left(2.5\,\frac{cm}{min} \right)$

$\frac{db}{dt} = -2.262\,\frac{cm}{min}$

The base of the triangle decreases at a rate of 2.262 centimeters per minute.

6 0

3 years ago

Kathy rolled a number cube that has sides labeled 1 to 6. What is the probability that she rolled a 2 or a 4?

kow [346]

It would be 2/6 or 1/3

4 0

3 years ago

Rewrite 163/4 in as many different ways as you can

VladimirAG [237]

There's an infinite number of ways we can rewrite 16 3/4, some of them being:

16 3/4
16 6/8
16 12/16
16 24/32
16.75
67/4
335/20
670/40
etc.

I hope it will help you ;)

4 0

3 years ago

Read 2 more answers

What is the slope of the line that passes through (4,1) and (7,-2)

valentina_108 [34]

(4,1)(7,-2)
slope = (-2 - 1) / (7 - 4) = -3/3 = -1

4 0

3 years ago

Read 2 more answers