Question

Given the line y=3/5x+2 find the perpendicular line passing through the point (12,-7)

Answer 1

Answer:

y=-5/3x+13.

Step-by-step explanation:

As a line that is perpendicular to anoher line has a slope that is the negative reciprocal of the line's original slope, we know that the slope of our new line is -5/3. As it passes point (12, -7), we can use the point slope formula which is y-y1=m(x-x1). So plug in, y+7=-5/3(x-12) and that gives us y+7=-5/3x+20 which gives our final answer of y=-5/3x+13.