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dimaraw [331]
3 years ago
13

Given the line y=3/5x+2 find the perpendicular line passing through the point (12,-7)

Mathematics
1 answer:
Monica [59]3 years ago
7 0

Answer:

y=-5/3x+13.

Step-by-step explanation:

As a line that is perpendicular to anoher line has a slope that is the negative reciprocal of the line's original slope, we know that the slope of our new line is -5/3. As it passes point (12, -7), we can use the point slope formula which is y-y1=m(x-x1). So plug in, y+7=-5/3(x-12) and that gives us y+7=-5/3x+20 which gives our final answer of y=-5/3x+13.

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The perimeter of a rectangle is 240 ft., If the length is 12 ft., then what is the width
Degger [83]

Answer:

w=108

Step-by-step explanation:

Using the formula

P=2(l+w)

Solving for w

w=P /2﹣l = 240 /2﹣12 = 108

8 0
3 years ago
Read 2 more answers
Simplify 5(cis7pi/4)^4
solniwko [45]

Answer:

  -625

Step-by-step explanation:

The magnitude gets raised to the power, and the angle gets multiplied by the power:

  5(cis7pi/4)^4 = (5^4)cis(4·7π/4) = 625cis(7π) = 625cis(π) = -625

5 0
3 years ago
ANSWER ?! <br><br> HELP.......
Anon25 [30]
26250m I think this is right
3 0
3 years ago
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3 | 2x – 3| -5 = 4<br><br> Absolute value equations
anyanavicka [17]

Answer:

3

Step-by-step explanation:

  1. 3 |2x -3| -5=4
  2. 3 |2x -3| =4+5
  3. 2x-3=9÷3
  4. 2x=3+3
  5. x=6÷2
  6. x=3
8 0
4 years ago
<img src="https://tex.z-dn.net/?f=-%283%5Ex-1%29%285%5Ex-1%29%2B1" id="TexFormula1" title="-(3^x-1)(5^x-1)+1" alt="-(3^x-1)(5^x-
Pachacha [2.7K]

Answer:

x = 0

Step-by-step explanation:

-[(3^x - 1)(5^x - 1)] + 1 = 1

Subtract 1 form both sides

-[(3^x - 1)(5^x - 1)] = 0

Divide both sides by -1

(3^x - 1)(5^x - 1) = 0

Equate the factors to 0

3^x - 1 = 0

3^x = 1

Use ln both sides

ln(3^x) = ln(1)

xln(3) = 0

x = 0

5^x - 1 = 0

5^x = 1

Use ln both sides

ln(5^x) = ln(1)

xln(5) = 0

x = 0

The only solution is x = 0

3 0
3 years ago
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