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Vesnalui [34]
2 years ago
12

What two integers does sqrt41 fall between? explain reasoning

Mathematics
2 answers:
VLD [36.1K]2 years ago
7 0

Let's check the squares of first 10 number

  • 1²=1
  • 2²=4
  • 3²=9
  • 4²=16
  • 5²=25
  • 6²=36
  • 7²=49
  • 8²=64
  • 9²=81
  • 10²=100

41 lies between 36 and 49

Hence

  • √41 lies in between 6 and 7
valina [46]2 years ago
5 0

Answer:

Below!

Step-by-step explanation:

Given square root:

\sqrt41

Let's note a few perfect square roots.

1 = \sqrt{1 \times 1} = \sqrt{1}

2 = \sqrt{2 \times 2} = \sqrt{4}

3 = \sqrt{3 \times 3} =\sqrt{9}

4 = \sqrt{4 \times 4} =\sqrt{16}

5 = \sqrt{5 \times 5} =\sqrt{25}

6 = \sqrt{6 \times 6} =\sqrt{36}

7 = \sqrt{7 \times 7} =\sqrt{49}

8 = \sqrt{8 \times 8} =\sqrt{64}

And so on...

When looking at the perfect square roots we identified, we can say that:

\sqrt{36} < \sqrt{41} < \sqrt{49}

Therefore,

6 < \sqrt{41} < 7

We can conclude that \sqrt{41} is between 6 and 7.

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