2 years ago

A Rectangular Room has a length of 3 more than its width. The perimeter of the room is 90. What is the width of the room?

Mathematics

1 answer:

nignag [31]2 years ago

4 0

The answer to your question is 21

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2/2

Step-by-step explanation:

There are only red and green jump ropes so she is for sure going to get a red or green jump rope. If she wants specifically a red or green jump rope her chances are 1/2.

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3 years ago

S (3, -5), T (0, -2), U (-3, -5) scale factor = 4 S' = T' = U'=

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S’(12,-20) T’(0,-8) U’(-12,-20)

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Find the value of the variable.

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Consider a rectangle with vertices A (4, 7), B (6, 7), C (4, -1), and D (6, -1). What is the length of side CD? What is the leng

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2 years ago

Read 2 more answers

The projected rate of increase in enrollment at a new branch of the UT-system is estimated by E ′ (t) = 12000(t + 9)−3/2 where E

nexus9112 [7]

Answer:

The projected enrollment is $\lim_{t \to \infty} E(t)=10,000$

Step-by-step explanation:

Consider the provided projected rate.

$E'(t) = 12000(t + 9)^{\frac{-3}{2}}$

Integrate the above function.

$E(t) =\int 12000(t + 9)^{\frac{-3}{2}}dt$

$E(t) =-\frac{24000}{\left(t+9\right)^{\frac{1}{2}}}+c$

The initial enrollment is 2000, that means at t=0 the value of E(t)=2000.

$2000=-\frac{24000}{\left(0+9\right)^{\frac{1}{2}}}+c$

$2000=-\frac{24000}{3}+c$

$2000=-8000+c$

$c=10,000$

Therefore, $E(t) =-\frac{24000}{\left(t+9\right)^{\frac{1}{2}}}+10,000$

Now we need to find $\lim_{t \to \infty} E(t)$

$\lim_{t \to \infty} E(t)=-\frac{24000}{\left(t+9\right)^{\frac{1}{2}}}+10,000$

$\lim_{t \to \infty} E(t)=10,000$

Hence, the projected enrollment is $\lim_{t \to \infty} E(t)=10,000$

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2 years ago