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Brrunno [24]
2 years ago
11

Pleas I need help now

Mathematics
1 answer:
Zina [86]2 years ago
8 0
I can't see the picture it is too small
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2x Y,

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On any day, the probability of rain is 0.3. The occurrence of rain on any day is independent of the occurrence of rain on any ot
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<h3>Answer: 0.47178  Step-by-step explanation: Find the probability for each p(X=x) up to 5 using the equation: (x-1)C(r-1)*p^r * q^x-r, where x is number of days, p = .3 (prob of rain). q=.7 (prob of not rain), and r=2 (second day of rain). also C means choose. So p(X=1) = 0 p(X=2) = 1C1 * .3^2 * .7^0 = .09 P(X=3) = 2C1 * .3^2 * .7^1 = .126 P(X=4) = 3C1 * .3^2 * .7^2 = .1323 P(X=5) = 4C1 * .3^2 * .7^3 = .12348 Then add all of them up 0+.09+.126+.1323+.12348 = .47178</h3>
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3 years ago
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siniylev [52]

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When 9 Superscript two-thirds is written in simplest radical form, which value remains under the radical?
salantis [7]

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  3

Step-by-step explanation:

9^{\frac{2}{3}}=(3^2)^{\frac{2}{3}}=3^{\frac{4}{3}}=3\cdot 3^{\frac{1}{3}}\\\\=3\sqrt[3]{3}

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