Answer:
Removing the outlier decreases the number of data by one and therefore you must decrease the divisor. For instance, when you find the mean of 0,10,10,12,12, you must divide the sum by 5, but when you remove the outlier of 0,you must then divide by 4.
Step-by-step explanation:
Answer:
1. D
2. E
3. B
4. C
5. A
5. F
Step-by-step explanation:
The <u>median</u> can be found at the line inside of the box, the <u>heaviest</u> weight would be found at the right end of the line, and the <u>smallest </u>weight would be found at the left, the <u>interquartile range</u> is the difference of one end of the box to the other, and the<u> range</u> is the difference of the largest number of the entire diagram, from the smallest number.
Hope this helps you!
Answer:
weight * (4 / 5) = 30
weight * .8 = 30
weight = 30 / .8
weight = 37.5 pounds
Step-by-step explanation:
<h2>
Exponential Functions</h2>
Exponential functions are typically organized in this format:
To find the equation given the graph of an exponential function:
- Identify the horizontal asymptote
⇒ <em>asymptote</em> - a line towards which a graph appears to travel but never meets
⇒ If the horizontal asymptote is not equal to 0, we add this at the end of the function equation. - Identify the y-intercept
⇒ This is our <em>a</em> value. - Identify a point on the graph and solve for <em>c</em>
<em />
<h2>Solving the Question</h2>
Identify the horizontal asymptote
In this question, it appears to be x = 0.
Identify the y-intercept
The y-intercept is the value of <em>y</em> at which the graph appears to cross the y-axis. In this graph, it appears to be 100. This is our <em>a</em> value. Plug this into :
Solve for <em>c</em>
We can use any point that falls on the graph for this step. For instance, (1,50) appears to be a valid point. Plug this into our equation and solve for <em>c</em>:
Plug <em>c</em> back into our original equation:
<h2>Answer</h2>
This definitely sounds like a question where there are
some choices listed but you decided not to share them.
Let's say you have several decimals that all look like this:
0.166
0.166666
0.1666
0.16666666666
0.16
.
.
The one with the most 6s is the closest to 1/6 .
Can you ever write a decimal that's exactly equal to 1/6 ?
No, you can't. The 6s go on forever, and never end.
The more 6s there are, the closer it is to 1/6, but it
can never be exactly 1/6 .
