Answer:
-1
Step-by-step explanation:
|x-4|=x-4 when x-4 is positive or zero.
|x-4|=-(x-4) when x-4 is negative or zero.
x-4 is positive or zero means:
x-4>=0
Add 4 on both sides gives:
x>=4
x-4 is negative or zero means:
x-4<=0
Add 4 on both sides gives:
x<=4
Now we are approaching values of 4 from the left which means these values are less than 4 which makes x-4 negative.
So we are using:
|x-4|=-(x-4) when x-4 is negative or zero.
As x approaches 4 from left we have:
|x-4|/(x-4)=-(x-4)/(x-4)=-1.
Let's find the discriminant of <span>x^2+9x+14=0. Here, a=1, b=9 and c=14.
The discriminant is b^2-4ac. Substituting the above numeric values,
9^2-4(1)(14) = 81-56 = 25
The sqrt of 25 is 5. Thus, your polynomial has two unequal, real roots.
Off the point example: If the discriminant were zero, your poly would have two real, equal roots.</span>
Answer if D hope it helps!
Answer: B, C, And F
Step-by-step explanation:
My answer is correct because, for the negative numbber whatever is close to 1 like -1 is greater then the other negative number.
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We start as 4 8 12 16 20 24that are all divided into the fourth
