Question

Help please with trigonometry hw please

Answer 1

In trig SIN is y/1 or r and TAN is Y/X so if SIN (y/1) is 0.8, tan would have to be 0.8/x. If an X is given you can solve

Answer 2

Answer:

okay let's go

Step-by-step explanation:

$\sin( theta) = 0.8 \\ 0.8 = \frac{4}{5} \\ if \: theta \: is \: 90 \\ \sin(theta) = \frac{opposite(4)}{hypotenuse(5)} \\ to \: get \: adjacent \: use \: pythagoras \: theorem \: adjacent = \sqrt{ {5}^{2} - {4}^{2} } \\ = 3 \\ therefore \: tan(theta) =\frac{4}{3}$