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IrinaVladis [17]
3 years ago
11

Is 5/8 grater than or equal to 11/16

Mathematics
1 answer:
expeople1 [14]3 years ago
5 0
Answer: it’s actually less than 11/16

Explanation: to get 5/8 to an equal numerator to compare the two, you’d have to multiply 5/8 by 2. That will be 10/16. Which is less than 11/16.
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2x divided by x+5 less than or equal to 0
coldgirl [10]
It is more than 0, because you cancel the x, and you get 2+5, which is 7
4 0
3 years ago
This . 9th and 10 pleasee solve thesee ?
kykrilka [37]
9 is 9600 cause if you divide 48 by 5 you get 9.6 then times 9.6 times 1000 you get 9600
i cant solve number 10 its really blurry and hard to see
5 0
3 years ago
HELP PLEASE!!! Picture below!
Lady_Fox [76]

Answer:

7 (units)

Step-by-step explanation:

If E is placed at the number 6- then it would take 6 to get to 0. If B is placed at -1, then it would be one more backward to get to B- so it would take 7 to get from E to B.

8 0
3 years ago
A triangle can have at most ________ right angle.
andrey2020 [161]
A triangle can only have at most one right angle.

Here's a proof that shows why this is so:

We know that the sum of all interior angles of a triangle must add up to 180.
Let's say the interior angles are A, B, and C

A + B + C = 180

Let's show that having two right angles is impossible

Let A = B = 90

90 + 90 + C = 180

180 + C = 180

Subtract 180 from both sides

C = 0

We cannot have an angle with 0 degrees in a triangle. Thus, it is impossible to have 2 right angles in a triangle.

Let's try to show that it's impossible to have 3 right angles

Let A = B = C = 90

90 + 90 + 90 = 180 ?

270 ≠ 180

Thus it's impossible to have 3 right angles as well.

Let's show that is possible to have 1 right angle

Let A = 90

90 + B + C = 180

Subtract both sides by 90

B + C = 90

There are values of B and C that will make this true. Thus, a triangle can have at most one right angle.

Have an awesome day! :)
3 0
3 years ago
A team is being formed that includes eight different people. There are eight different positions on the teams. How many differen
abruzzese [7]

Answer:

40320 different ways

Step-by-step explanation:

That problem is a permutation one

We have eight people to occupy  one position in a team, without any constraint at all

So

Total number of events   = P(8)

P (8)  =  8!

P (8)  =  8*7*6*5*4*3*2*1

P (8)  =  40320 different ways

6 0
3 years ago
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