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DENIUS [597]
2 years ago
5

Which of these are examples of a statistical question's?

Mathematics
1 answer:
viktelen [127]2 years ago
4 0

Answer:

See below for answers and explanations

Step-by-step explanation:

A is not a statistical question because there's only a specific value of computers in the lab

B is not a statistical question because there is only one answer, which is 9 letters

C is a statistical question because members can have different favorites (or they find it hard to choose one).

D is not a statistical question because there is only one amount of people that helped out.

E is not a statistical question because each student purchased their own amount of video games and data can be collected for each individual student

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bagirrra123 [75]

Answer:

they reflected over the y axis instead of the x.

6 0
3 years ago
Why are (4, 6) and (6, 4) not at the same point on a grid?
sdas [7]

Answer and Step-by-step explanation:

Notice that both these points are in the form of (x, y). "x" indicates that on the left-right axis (x axis), the point is x units away from the origin (0, 0). "y" indicates that on the up-down axis (y axis), the point is y units away from the origin.

In (4, 6), x = 4 and y = 6. This means that the point (4, 6) is 4 units to the right of the origin and 6 units up (see red dot on attachment).

In (6, 4), x = 6 and y = 4. This means that the point (6, 4) is 6 units to the right of the origin and 4 units up (see blue dot on attachment).

As can be seen, these two points do NOT coincide, so they are different.

6 0
3 years ago
Read 2 more answers
Write seventy-one and one hundred sixty-four thousandths as a decimal number.
Monica [59]

Answer:

0.0071164

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Find the perimeter of the polygon with vertices A(-6,-4), B(-3,6), C(4,0), and D(2,-1)?
EleoNora [17]
Check the picture below.

so the perimeter of the polygon is the sum of all its sides, namely, AB + BC + CD + DA.

now, let's check how long each side is,

\bf ~~~~~~~~~~~~\textit{distance between 2 points}\\ \quad \\
\begin{array}{ccccccccc}
&&x_1&&y_1&&x_2&&y_2\\
%  (a,b)
&A&(~{{ -6}} &,&{{ -4}}~) 
%  (c,d)
&B&(~{{ -3}} &,&{{ 6}}~)
\end{array}
\\\\\\
d = \sqrt{({{ x_2}}-{{ x_1}})^2 + ({{ y_2}}-{{ y_1}})^2}\\\\
-------------------------------\\\\
AB=\sqrt{[-3-(-6)]^2+[6-(-4)]^2}
\\\\\\
AB=\sqrt{(-3+6)^2+(6+4)^2}
\\\\\\
AB=\sqrt{3^2+10^2}\implies \boxed{AB=\sqrt{109}}\\\\
-------------------------------

\bf ~~~~~~~~~~~~\textit{distance between 2 points}\\ \quad \\
\begin{array}{ccccccccc}
&&x_1&&y_1&&x_2&&y_2\\
%  (a,b)
&B&(~{{ -3}} &,&{{6}}~) 
%  (c,d)
&C&(~{{ 4}} &,&{{ 0}}~)
\end{array}
\\\\
-------------------------------\\\\
BC=\sqrt{[4-(-3)]^2+[0-6]^2}\implies BC=\sqrt{(4+3)^2+(0-6)^2}
\\\\\\
BC=\sqrt{7^2+(-6)^2}\implies \boxed{BC=\sqrt{85}}\\\\
-------------------------------

\bf ~~~~~~~~~~~~\textit{distance between 2 points}\\ \quad \\
\begin{array}{ccccccccc}
&&x_1&&y_1&&x_2&&y_2\\
%  (a,b)
&C&(~{{ 4}} &,&{{0}}~) 
%  (c,d)
&D&(~{{ 2}} &,&{{ -1}}~)
\end{array}
\\\\
-------------------------------\\\\
CD=\sqrt{(2-4)^2+(-1-0)^2}\implies CD=\sqrt{(-2)^2+(-1)^2}
\\\\\\
\boxed{CD=\sqrt{5}}\\\\
-------------------------------

\bf ~~~~~~~~~~~~\textit{distance between 2 points}\\ \quad \\
\begin{array}{ccccccccc}
&&x_1&&y_1&&x_2&&y_2\\
%  (a,b)
&D(~{{ 2}} &,&{{-1}}~) 
%  (c,d)
&A&(~{{ -6}} &,&{{ -4}}~)
\end{array}\\\\
-------------------------------\\\\
DA=\sqrt{[-6-2]^2+[-4-(-1)]^2}\\\\\\ DA=\sqrt{(-6-2)^2+(-4+1)^2}
\\\\\\
DA=\sqrt{(-8)^2+(-3)^2}\implies \boxed{DA=\sqrt{73}}

sum those sides up, and that's the perimeter of the polygon.

6 0
3 years ago
Test the claim that the proportion of men who own cats is smaller than the proportion of women who own cats at the .10 significa
nata0808 [166]

Answer:

 The  test statistics is t  =   -1.40

  The critical value is  Z_{\alpha }   = 2.33

   The null hypothesis is rejected

Step-by-step explanation:

From the question we are told that

   The sample size  for men is  n_1 =  80

    The sample  proportion of men that own a cat is  \r p _M  =  0.40

     The  sample  size for  women is n_2  =  80

     The sample  proportion of women that own a cat is  \r p_F  =  0.51

     The level of significance is  \alpha  =  0.10

   The  null hypothesis is  H_o  :  \r p _M   =  \ r P_F

    The alternative hypothesis is  H_a  :  \r p _M  <  \r p_F

Generally the test statistic is mathematically represented as

        t  =    \frac{(\r p_M - \r p_F)}{\sqrt{\frac{(p_M*(1-p_M)}{n_1 } }  +  \frac{p_F*(1-pF)}{n_2 } }

=>  t  =    \frac{(0.40  - 0.51)}{\sqrt{\frac{(0.40 *(1-0.41)}{80} }  +  \frac{0.51*(1-0.51)}{80 } }

=>   t  =   -1.40

The critical value of  \alpha  from the normal distribution table is

     Z_{\alpha }   = 2.33

The p-value  is obtained from the z-table ,the value is  

    p-value =  P( Z < -1.40) =   0.080757

=>    p-value = 0.080757

Given that the p-value  <  \alpha then we reject the null hypothesis

7 0
3 years ago
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