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Masja [62]
3 years ago
6

The half-life of a radioactive kind of neodymium is 11 days. If you start with 2,616 grams of it, how much will be left after 22

days?
Mathematics
1 answer:
Ket [755]3 years ago
3 0

Answer:

654 grams

Step-by-step explanation:

When you set up this equation you want the number of grams you start with, 2616, and the factor by which it is decreasing, which is half, or 1/2. Because the half life is 11 days, but you want to find the amount left over after 22 days, you can make 22/11 as the exponent on the 1/2. The equation should look like this : 2616(1/2)^22/11. With these kinds of equations you always want to multiply the starting value by the factor of increase/decrease, and raise that factor to the time eclipsed divided by the set time(like the 11 day half life).

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alex41 [277]

Answer:

do you need help with the L and P???????

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
I know only one answer whats the other one help me image-
miv72 [106K]

Answer:

A. 4(4a + 18)

B. 8(2a + 9)

Step-by-step explanation:

<u><em>We know that</em></u> :

16a = 4×4×a

72 = 4×18

Then

16a + 72 = 4×(4a) + 4×(18)

              = 4 × (4a + 18)

On the other hand,

16a = 8×2×a

72 = 8×9

Then

16a + 72 = 8×(2a) + 8×(9)

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7 0
1 year ago
If discriminant (b^2 -4ac&gt;0) how many real solutions
MaRussiya [10]

Answer:

If Discriminant,b^{2} -4ac >0

Then it has Two Real Solutions.

Step-by-step explanation:

To Find:

If discriminant (b^2 -4ac>0) how many real solutions

Solution:

Consider a Quadratic Equation in General Form as

ax^{2} +bx+c=0

then,

b^{2} -4ac is called as Discriminant.

So,

If Discriminant,b^{2} -4ac >0

Then it has Two Real Solutions.

If Discriminant,b^{2} -4ac < 0

Then it has Two Imaginary Solutions.

If Discriminant,b^{2} -4ac=0

Then it has Two Equal and Real Solutions.

4 0
3 years ago
Kate is going to purchase a coat for $38, pants for $45, and 2 pairs of shoes for $34 each. if she has $180 to spend how much mo
likoan [24]
She would have 20 dollars left over. take the amount of money she has then add up all of the cost of the stuff she will buy then subtract.
5 0
3 years ago
When obtaining a confidence interval for a population mean in the case of a finite population of size N and a sample size n whic
Elanso [62]

Answer:

95% Confidence interval for the mean

142.8 \leq\mu\leq158.4

Step-by-step explanation:

We have to calculate a 95% confidence interval for the mean of a finite population.

The error is multiplied by the following finite population correction factor:

cf=\sqrt{\frac{N-n}{N-1} }

The standard deviation can be estimated as

\sigma=\frac{s}{\sqrt{n}} \sqrt{\frac{N-n}{N-1} } =\frac{24.4}{\sqrt{32} }* \sqrt{\frac{200-32}{200-1} }=3.963

The 95% confidence interval has a z value of 1.96, so it becomes:

M-z*\sigma_c\leq\mu\leq M+z*\sigma_c\\\\150.6-1.96*3.963\leq\mu\leq 150.6+1.96*3.963\\\\ 142.8 \leq\mu\leq 158.4

5 0
3 years ago
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